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Svetradugi [14.3K]
4 years ago
6

9x-6=180 What does x equal in this equation

Mathematics
1 answer:
raketka [301]4 years ago
7 0

Answer:

X=20.6666

Step-by-step explanation:

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Use a projector do you have one?

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I need help on this ASAP!!!!!!<br><br> (image attached and it's find X)
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4 years ago
You are running a race. The probability that you win is 3/5. What is the probability that you lose at most 2 out of your 6 races
Veronika [31]

Answer:

The probability that you lose at most 2 out of your 6 races is 0.54432.

Step-by-step explanation:

We are given that you are running a race. The probability that you win is 3/5.

There are total of 6 races.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 6 races

            r = number of success = at most 2 lost

            p = probability of success which in our question is probability that

                  you lose a race =  1 - (3/5) = 2/5 or 0.4

Let X = <u><em>Number of races lost </em></u>

So, X ~ Binom(n = 6, p = 0.40)

Now, the probability that you lose at most 2 out of your 6 races is given by = P(X \leq 2)

P(X \leq 2)  =  P(X = 0) + P(X = 1) + P(X = 2)

=  \binom{6}{0} \times 0.40^{0} \times (1-0.40)^{6-0} + \binom{6}{1} \times 0.40^{1} \times (1-0.40)^{6-1} + \binom{6}{2} \times 0.40^{2} \times (1-0.40)^{6-2}  

=  1 \times1 \times 0.60^{6} + 6 \times 0.40^{1} \times 0.60^{5} +15\times 0.40^{2} \times 0.60^{4}  

=  <u>0.54432</u>

7 0
3 years ago
Retro Rides is a club for owners of vintage cars and motorcycles. Every year the club gets together for a ride. This year, 38 ve
alina1380 [7]

Answer: OPTION B

Step-by-step explanation:

Let's call:

c: the number of cars.

m: the number of motorcycles.

Based on the given information, you can set up the following system of equations:

\left \{ {{c+m=38} \atop {4c+2m=104}} \right.

You can solve it by the Elimination method:

- Multiply the first equation by -4.

- Add both equations to cancel out the variable "c".

- Solve for "m":

\left \{ {(-4)(c+m)=38(-4)} \atop {4c+2m=104}} \right.\\\\\left \{ {-4c-4m=-152} \atop {4c+2m=104}} \right.\\-------\\-2m=-48\\m=24

(24 motorcycles)

 - Substitute m=24 into any of the original equations ans solve for "c". Then:

c+24=38\\c=38-24\\c=14

(14 cars)

6 0
4 years ago
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Solve 5x &gt; 10<br> help this is very confusing how do i do this
Leokris [45]

Answer:

Simplify to (2,∞) or X>2

6 0
3 years ago
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