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kykrilka [37]
4 years ago
6

For the function f(x)=x^2-x determine f(x-2) in simplest form

Mathematics
1 answer:
tiny-mole [99]4 years ago
3 0
Easy, sub x-2 for x
f(x-2)=(x-2)^2-(x-2)
expand
f(x-2)=(x^2-2x-2x+4)-(x-2)
f(x-2)=(x^2-4x+4)-x+2
f(x-2)=x^2-5x+6
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