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Anuta_ua [19.1K]

2 years ago

15

The temperature right now is -1° F and the forecasted high temperature is 2° F. How many degrees will it have to warm to reach 2

° F?

2 answers:

Svet_ta [14]2 years ago

5 0

Answer:

3 degrees Fahrenheit.

Step-by-step explanation: The difference between -1 and 2 is 3.

Zepler [3.9K]2 years ago

5 0

Answer:

3

Step-by-step explanation:

because 1 plus -1 is 0 plus 2 is 2 and 1 plus 2 is 3

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Yuliya22 [10]

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Is 12.91 a rational number

Musya8 [376]

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Step-by-step explanation:

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3 years ago

The Charleston family has less than 500 Dalmatians. There are six times as many Dalmatians with black spots on their right ears

ANEK [815]

Let x be the number of Dalmatians without black spots.
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7 0

3 years ago

Read 2 more answers

Plz show work and solve quick please need help!!!!!

Simora [160]

Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

$\sf A=lw$

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

$\sf A=(56)(27)$

$\sf A=1512cm^2$

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

$\sf 82.8-28=54.8\? cm$

Calculate the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(27)(54.8)$

$\sf A=739.8\?cm^2$

We have two of these triangles.

$\sf 739.8\times 2=1479.6\? cm^2$

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

$\sf 81.2-27=54.2\?cm$

Now find the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(56)(54.2)$

$\sf A=1517.6\? cm^2$

We have two of these triangles.

$\sf 1517.6\times 2=3035.2\?cm^2$

Add all the areas together:

$\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}$

7 0

3 years ago

I need help on #10. very confused

RideAnS [48]

Step-by-step explanation:

$\displaystyle f'(x) = \lim_{h \to 0} \dfrac{f(x + h) - f(x)}{h}$

$\:\:\:\:\:\displaystyle = \lim_{h \to 0} \dfrac{(x+h)^2 -7 -(x^2 - 7)}{h}$

$\:\:\:\:\: \displaystyle= \lim_{h \to 0} \dfrac{(x^2 +2hx + h^2 -7) - (x^2 -7)}{h}$

$\:\:\:\:\: \displaystyle= \lim_{h \to 0} \dfrac{2hx + h^2}{h}$

$\:\:\:\:\: \displaystyle= \lim_{h \to 0} (2x +h)$

$\:\:\:\:\: \displaystyle= 2x$

3 0

2 years ago