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Bas_tet [7]
3 years ago
13

How do you know the value of x?

Mathematics
1 answer:
lidiya [134]3 years ago
5 0
To find the value of X you would have to solve the equation.
Example: for question 2



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Which angels are obtuse?
xxMikexx [17]

obtuse angles are having value greater than 90 degree.

so ans is option A

angle DBC is greater than 90

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4 years ago
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The area of the shaded region to the nearest tenth is __________.
goldfiish [28.3K]

Answer: 380 ft^2

Step-by-step explanation:

Length of sides of square=25

Diameter of semicircle=25

Radius=r=25/2=12.5

π=3.14

Area of square=length x length

Area of square=25 x 25=625

Area of semicircle=0.5 x π x r x r

Area of semicircle=0.5 x 3.14 x 12.5 x 12.5

Area of semicircle=245.3125

Area of shaded portion=area of square - area of semicircle

Area of shaded portion=625-245.3125

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Area of shaded portion=380ft^2

approximately

4 0
3 years ago
How you could use paper folding to construct the bisector of an angle
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<span>This really works well with wax paper. It is transparent and it leaves a visible white line on the crease. For the perpendicular bisector of a line segment, fold the endpoints of the line segment onto each other. The crease is the perpendicular bisector. This of course also gives you the midpoint, because that is where the perpendicular bisector intersects the line segment. For an angle bisector, put the crease through the vertex of the angle and lay the sides of the angle over top of each other. The crease is the angle bisecto



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3 years ago
Fourteen students got a B on the last quiz. This represents 2/5 of the class. How many students are in the class?
Elena-2011 [213]
3/5 of the class is left
5 0
3 years ago
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The prism has a volume of 120 cm3. What would the volume of the prism be if each dimension were halved? cm3 Triangular prism wit
Citrus2011 [14]
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a = 240 / ( c x h)
If the dimensions where halved then a = a/2 ; c = c/2 ; h=h/2
We use the volume formula again and substitute the given values to find the new volume,
V = 1/2 x a/2 x c/2 x h/2
Substitute the previously determined a term,
V = 1/2 x (240/2ch) x c/2 x h/2
We cancel and evaluate the constants therefore the new volume is,
V= 15 cm^3
3 0
4 years ago
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