obtuse angles are having value greater than 90 degree.
so ans is option A
angle DBC is greater than 90
Answer: 380 ft^2
Step-by-step explanation:
Length of sides of square=25
Diameter of semicircle=25
Radius=r=25/2=12.5
π=3.14
Area of square=length x length
Area of square=25 x 25=625
Area of semicircle=0.5 x π x r x r
Area of semicircle=0.5 x 3.14 x 12.5 x 12.5
Area of semicircle=245.3125
Area of shaded portion=area of square - area of semicircle
Area of shaded portion=625-245.3125
Area of shaded portion=379.6875
Area of shaded portion=380ft^2
approximately
<span>This really works well with wax paper. It is transparent and it leaves a visible white line on the crease. For the perpendicular bisector of a line segment, fold the endpoints of the line segment onto each other. The crease is the perpendicular bisector. This of course also gives you the midpoint, because that is where the perpendicular bisector intersects the line segment. For an angle bisector, put the crease through the vertex of the angle and lay the sides of the angle over top of each other. The crease is the angle bisecto
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The volume of a triangular prism is V = 1/2 x a x c x h where a is height of the triangle, c is the base of the triangle and h is the height of the prism.
120 = 1/2 x a x c x h; we write a from the previous equation in terms of c and h thus,
a = 240 / ( c x h)
If the dimensions where halved then a = a/2 ; c = c/2 ; h=h/2
We use the volume formula again and substitute the given values to find the new volume,
V = 1/2 x a/2 x c/2 x h/2
Substitute the previously determined a term,
V = 1/2 x (240/2ch) x c/2 x h/2
We cancel and evaluate the constants therefore the new volume is,
V= 15 cm^3