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RSB [31]
3 years ago
11

C+(4-3c)-2=0 Need help

Mathematics
1 answer:
Illusion [34]3 years ago
6 0
c+(4-3c)-2=0\\ \\c+ 4-3c -2=0\\ \\c-3c=2-4\\ \\-2c=-2 \ \ /:(-2)\\\\c=1


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Help! I need the answer and work to this :(
kompoz [17]
Since FA || BE, then angle 1 must equal angle 2 since they are corresponding angles along parallel lines where the transverse line cuts.
Thus, if angle 1 is 59, then angle 2 must also be 59 (ie D)
4 0
3 years ago
a sequence starts a 200 and 30 is subtracted each time 200,170,140 what are the first two numbers in the sequence that are kess
Snowcat [4.5K]
<h3>Answer:  -10 and -40</h3>

===============================================================

Explanation:

a = 200 = first term

d = -30 = common difference

Tn = nth term

Tn = a + d(n-1)

Tn = 200 + (-30)(n-1)

Tn = 200 - 30n + 30

Tn = -30n + 230

Set Tn less than 0 and isolate n

Tn < 0

-30n + 230 < 0

230 < 30n

30n > 230

n > 230/30

n > 7.667 approximately

Rounding up to the nearest whole number gets us n \ge 8

So Tn starts to turn negative when n = 8

We can see that,

Tn = -30n + 230

T7 = -30*7 + 230

T7 = 20

and

Tn = -30n + 230

T8 = -30*8 + 230

T8 = -10 is the 8th term

and lastly

Tn = -30n + 230

T9 = -30*9 + 230

T9 = -40 is the ninth term

Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.

5 0
3 years ago
Read 2 more answers
Students roll a 6-sided number cube and spin the shown spinner. blue blue orange red orange red orange purple What is the probab
Ede4ka [16]

Answer:

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6 0
3 years ago
(a) An article in a medical journal suggested that approximately 14% of such operations result in complications. Using this esti
aev [14]

This question is incomplete, the complete question is;

Surgical complications: A medical researcher wants to construct a

99.5% confidence interval for the proportion of knee replacement surgeries that result in complications.

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Step-by-step explanation:

Given that;

confidence interval = 99.5% = 0.995 so

margin of error E = 0.08

p = 14% = 0.14

now we obtain the critical value of z t the 99.5 confidence interval

∝ = 1 - confidence interval

∝ = 1 - 0.995

∝ = 0.005

∝/2 = 0.0025

obtaining the area of probability in the right tail

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from probability table; critical value of t =2.81

using the formula

n = p( 1 - p ) [ (z_∝/2)/E)² ]

so we substitute  

n = 0.14 ( 1 - 0.14 ) [ 2.81 / 0.08 )²  

n = (0.14 × 0.86 ) × 1233.7656

n = 148.5453 ≈ 149

Therefore , a sample of operations needed is 149

4 0
3 years ago
Oranges sell for $5.00 per bag. If there are 10 oranges in each bag, how much is the price per orange?
yulyashka [42]

Answer:

The answer is A

Step-by-step explanation:

10 divided by 5

8 0
3 years ago
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