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bekas [8.4K]
3 years ago
6

Write a function called activity which takes an integer parameter X that does the following:

Computers and Technology
1 answer:
vodomira [7]3 years ago
8 0

Answer:

here is code in java.

import java.util.*;

class Main

{

//  main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // Scanner class object to read the input integer

       Scanner scr=new Scanner(System.in);

       // ask user to enter the input

       System.out.print("enter a number:");

       // read the input

       int x=scr.nextInt();

       // call the function with parameter "x"

       activity(x);

       

   }catch(Exception ex){

       return;}

}

// activity function to perform given tasks

public static void activity(int x)

{

    // print all the Numbers from 1 to x

    System.out.print("Numbers:");

    for(int i=1;i<=x;i++)

    {

        System.out.print(i+" ");

    }

     System.out.println();

    // print all the Evens from 1 to x

     System.out.print("Evens:");

     for(int i=1;i<=x;i++)

    {

        if(i%2==0)

        System.out.print(i+" ");

    }

     System.out.println();

     // replace divisible of 5 and 7 with "fiver" and "ssss"

     System.out.print("Activity:");

     for(int i=1;i<=x;i++)

    {

        if(i%5==0)

        System.out.print("fiver ");

        else if(i%7==0)

        System.out.print("ssss ");

        else

        System.out.print(i+" ");

    }    

}

}

Explanation:

Read an integer with the help of Scanner class object and assign it to variable "x". Call the function activity() with parameter "x". In the activity function, first print "Numbers" followed by all numbers from 1 to X. Then print header "Evens" followed by all the even number from 1 to x. In last print "Activity" header followed by numbers from 1 to x and replace a number with "fiver" if it is divisible by 5 or replace with "ssss" if it  divisible by 7.

Output:

enter a number:17                                                                                                          

Numbers:1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17                                                                          

Evens:2 4 6 8 10 12 14 16                                                                                                  

Activity:1 2 3 4 fiver 6 ssss 8 9 fiver 11 12 13 ssss fiver 16 17  

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e-lub [12.9K]

Answer:

See explaination

Explanation:

dateType.h

#ifndef dateType_H

#define dateType_H

class dateType

{

public:

void setDate(int month, int day, int year);

//Function to set the date.

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day;

// dYear = year

int getDay() const;

//Function to return the day.

//Postcondition: The value of dDay is returned.

int getMonth() const;

//Function to return the month.

//Postcondition: The value of dMonth is returned.

int getYear() const;

//Function to return the year.

//Postcondition: The value of dYear is returned.

void printDate() const;

//Function to output the date in the form mm-dd-yyyy.

void isLeapYear() const;

dateType(int month = 1, int day = 1, int year = 1900);

//Constructor to set the date

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day; dYear = year;

// If no values are specified, the default

// values are used to initialize the member

// variables.

private:

int dMonth; //variable to store the month

int dDay; //variable to store the day

int dYear; //variable to store the year

};

#endif

dateType.cpp

#include <iostream>

#include "dateType.h"

using namespace std;

void dateType::setDate(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

int dateType::getDay() const

{

return dDay;

}

int dateType::getMonth() const

{

return dMonth;

}

int dateType::getYear() const

{

return dYear;

}

void dateType::printDate() const

{

cout << dMonth << "-" << dDay << "-" << dYear;

}

void dateType::isLeapYear() const

{

if ( dYear%400 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%100 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%4 == 0 )

cout<<endl<<dYear<< " is leap year.\n";

else

cout<<endl<<dYear<< " is not leap year.\n";

}

//Constructor with parameters

dateType::dateType(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

main.cpp

#include<iostream>

#include "dateType.h"

using namespace std;

int main()

{

dateType *dt1=new dateType();

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

dateType *dt2=new dateType(11,14,2019);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt2->setDate(13,32,2016);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt1->setDate(10,10,198);

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

system("pause");

return 0;

}

6 0
3 years ago
Que es un sistema . .
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3 0
3 years ago
Write a program to read customer number, Name, loan amount, interest rate and time of repayment. Calculate and display the EMI .
kompoz [17]

Answer:

The programming language is not stated; however, I'll answer this question using Python programming language.

This program doesn't make use of comments (See Explanation Section for detailed explanation)

The program is as follows

name = input("Customer Name: ")

number = input("Customer Number: ")

loan = float(input("Loan Amount: "))

rate = float(input("Interest Rate: "))

time = int(input("Repayment Time [in months] : "))

Interest = loan * (1 + rate/100) ** time

EMI = (Interest + loan)/time

print("EMI: ", end='')

print(round(EMI,2))

Explanation:

This line prompts for customers' name

name = input("Customer Name: ")

This line prompts for customers'number

number = input("Customer Number: ")

This line prompts for loan amount

loan = float(input("Loan Amount: "))

The line prompts for the interest rate

rate = float(input("Interest Rate: "))

This line prompts for time of loan repayment

time = int(input("Repayment Time [in months] : "))

Using the given formula, this line calculates the interest amount

Interest = loan * (1 + rate/100) ** time

The EMI is calculated using this line

EMI = (Interest + loan)/time

This line prints the string "EMI: " without the quotes

print("EMI: ", end='')

The last line of the program prints the calculated value of EMI, rounding it up to 2 decimal places

print(round(EMI,2))

6 0
3 years ago
Please help! Due by tonight! Greatly appreciated!
Helga [31]

Answer:

Im sorry if im wrong but i took a class for coding a long time ago but i think  it is 6 :)

6 0
3 years ago
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