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Sindrei [870]
3 years ago
9

Name the major types of computer systems from slowest to fastest. ​

Computers and Technology
1 answer:
Vadim26 [7]3 years ago
3 0

Answer:

Cache is the fastest and most expensive, RAM is slower and less expensive, and virtual memory is the slowest and least expensive type.

Explanation:

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Book checkout scenario at a library: The Worker tells the System the identity of a patron who wishes to check out books. The Sys
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Answer:

Check the explanation

Explanation:

To solve the above question.

The two valid classes are:

1. Patron_identity

2. Books

Class generalization can be between Books and Patrol_identity to create a new superclass for All The Books that this patron has ever checked out.

Two valid associations can be between:

1.Patron_identity and books

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3 years ago
To keep a desktop computer or a server powered up when the electricity goes off in addition to protection against power fluctuat
pickupchik [31]

To keep a desktop computer or a server powered up when the electricity goes off in addition to protection against power fluctuations, an <u>uninterruptible power supply (UPS)</u>, which contains a built-in battery, can be used.

<u>Explanation</u>:

An uninterruptible power supply (UPS) is a device that allows a computer or server powered up for a short time, when the electricity goes off. UPS device also provides uninterrupted service during power fluctuation.

A battery is inbuilt in the UPS and provides power for few minutes to the computer to shut down it in a proper manner.

UPS is available at affordable cost and can be maintained at low cost compared to generators.

8 0
3 years ago
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marin [14]

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8 0
3 years ago
Byte pair encoding is a data encoding technique. The encoding algorithm looks for pairs of characters that appear in the string
nika2105 [10]

Answer:

The encoding algorithm looks for pairs of characters that appear in the string more than once and replaces each instance of that pair with a corresponding character that does not appear in the string. ... Byte pair encoding is an example of a lossy transformation because it discards some of the data in the original string.

Explanation:

hope it helps!!

6 0
2 years ago
Using Amdahl’s Law, calculate the speedup gain of an application that has a 60 percent parallel component for (a) two processing
Nina [5.8K]

Answer:

a) Speedup gain is 1.428 times.

b) Speedup gain is 1.81 times.

Explanation:

in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

t=\frac{1 }{(S + (1- S)/N) }

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.

(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t = \frac{1}{(0.4 + (1-0.4)/2)} =1428671

Speedup gain is 1.428 times.

(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4

Thus, the speedup is:

t=\frac{1}{(0.4 + (1-0.4)/4)} = 1.8181

Speedup gain is 1.81 times.

8 0
3 years ago
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