9514 1404 393
Answer:
12 1/2 laps
Step-by-step explanation:
To find the number of laps, divide the distance by the distance per lap.
(3 1/8) ÷ (1/4) = (3 1/8) × (4/1) = 3·4 +(1/8)·4 = 12 4/8 = 12 1/2
Quadir needs to jog 12 1/2 laps if he wants to jog 3 1/8 miles.
Answer:
The specific gravity of kerosene is 0.82
Step-by-step explanation:
Let
x -----> the weight in grams of a cubic centimeter of Kerosene
y ----> the weight in grams of a cubic centimeter of water
z ---> the specific gravity of a substance
so
we have
substitute the values
<span>If you have an equilateral triangle, the median is also the altitude so - That means that if you draw altitude, it will bisect the base of the triangle and meet at two right angles. That gives you two of the measurements for the right triangle - the side (6) hypotenuse, and the base (3). You can then figure out the height using the Pythagorean as you have the a and the c for the theorem. Then you can use 1/2 base times height to find the area.
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Answer:
Step-by-step explanation:
![CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=CI%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%266%260%5C%5C0%261%262%5C%5C1%26-1%263%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
Subtract row 3 from row 1:
![\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%266%260%5C%5C0%261%262%5C%5C0%267%26-3%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C1%260%26-1%5Cend%7Barray%7D%5Cright%5D)
Subtract row 3 from 7 times row 2:
![\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%266%260%5C%5C0%261%262%5C%5C0%260%2617%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C-1%267%261%5Cend%7Barray%7D%5Cright%5D)
Divide row 3 by 17:
![\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%266%260%5C%5C0%261%262%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C%5Cfrac%7B-1%7D%7B17%7D%20%26%5Cfrac%7B7%7D%7B17%7D%20%26%5Cfrac%7B1%7D%7B17%7D%20%5Cend%7Barray%7D%5Cright%5D)
Subtract 2 of row 3 from row 2:
![\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%266%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C%5Cfrac%7B2%7D%7B17%7D%20%26%5Cfrac%7B3%7D%7B17%7D%20%26%5Cfrac%7B-2%7D%7B17%7D%20%5C%5C%5Cfrac%7B-1%7D%7B17%7D%20%26%5Cfrac%7B7%7D%7B17%7D%20%26%5Cfrac%7B1%7D%7B17%7D%20%5Cend%7Barray%7D%5Cright%5D)
Subtract 6 of row 2 from row 1:
![\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B5%7D%7B17%7D%26%5Cfrac%7B-18%7D%7B17%7D%26%5Cfrac%7B12%7D%7B17%7D%5C%5C%5Cfrac%7B2%7D%7B17%7D%20%26%5Cfrac%7B3%7D%7B17%7D%20%26%5Cfrac%7B-2%7D%7B17%7D%20%5C%5C%5Cfrac%7B-1%7D%7B17%7D%20%26%5Cfrac%7B7%7D%7B17%7D%20%26%5Cfrac%7B1%7D%7B17%7D%20%5Cend%7Barray%7D%5Cright%5D)
![C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]](https://tex.z-dn.net/?f=C%5E%7B-1%7D%3D%5Cfrac%7B1%7D%7B17%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-18%2612%5C%5C2%263%26-2%5C%5C-1%267%261%5Cend%7Barray%7D%5Cright%5D)
![C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]](https://tex.z-dn.net/?f=C%5E%7B-1%7Db%3D%5Cfrac%7B1%7D%7B17%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-18%2612%5C%5C2%263%26-2%5C%5C-1%267%261%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D10%261%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D4%261%260%5Cend%7Barray%7D%5Cright%5D)
Hi!
This fraction converted to a decimal number is 0.7 with the 7 repeating
0.7777777777777777777777777777777777777777...∞
