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2 years ago

Someoneee pleaseee helppp!!!!

Mathematics

1 answer:

Andreas93 [3]2 years ago

3 0

Answer:

Step-by-step explanation:

Angles 3, 4, and 5 are supplementary to each other, meaning that all of them added together equal 180. Therefore, to solve for x:

x + 18 + x + 15 + 4x + 3 = 180 and

6x + 36 = 180 and

6x = 144 so

x = 24

Angles 1 and 3 are vertical angles, so they are congruent, meaning they both have the exact same angle measure. If angle 3 measures, x + 18, so does angle 1. If x = 24, then angle 1 = 24 + 18 which is 42 degrees.

That also answered part c. Angles 1 and 3 are not complementary, they are vertical.

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djverab [1.8K]

Answer:

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Step-by-step explanation:

So this is basically saying that for every 1 second that passed, 8 oz of water drip steadily into the bucket which can be expressed like this:

8w = t

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w = 1/8t

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2 years ago

Which expression can be used to convert AU$22 in the US dollars

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3 years ago

Geometry proofs. Prove Angle B = Angle C

koban [17]

Answer: It is vertical

Step-by-step explanation:

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2 years ago

Tatiana is practicing shooting. The coordinates (in m) of the barrel of her gun and the target are (5, 3, 1) and (38, 41, 3). Wh

saul85 [17]

Answer:

$d=\sqrt{2,537}\ m$ or $d=50.37\ m$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points in three dimensions is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}+(z2-z1)^{2}}$

Let

$A(5,3,1)$ -----> coordinates of the barrel of her gun

$B(38,41,3)$ -----> coordinates of the target

substitute the values

$d=\sqrt{(41-3)^{2}+(38-5)^{2}+(3-1)^{2}}$

$d=\sqrt{(38)^{2}+(33)^{2}+(2)^{2}}$

$d=\sqrt{1,444+1,089+4}$

$d=\sqrt{2,537}\ m$

$d=50.37\ m$

7 0

2 years ago

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago