Someoneee pleaseee helppp!!!!

Mathematics

1 answer:

Andreas93 [3]3 years ago

3 0

Answer:

Step-by-step explanation:

Angles 3, 4, and 5 are supplementary to each other, meaning that all of them added together equal 180. Therefore, to solve for x:

x + 18 + x + 15 + 4x + 3 = 180 and

6x + 36 = 180 and

6x = 144 so

x = 24

Angles 1 and 3 are vertical angles, so they are congruent, meaning they both have the exact same angle measure. If angle 3 measures, x + 18, so does angle 1. If x = 24, then angle 1 = 24 + 18 which is 42 degrees.

That also answered part c. Angles 1 and 3 are not complementary, they are vertical.

You might be interested in

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$