Plz help me i need help w this algebra

docker41 [41]

Given =

Two similar pyramid have base area of 12.2 cm² and 16 cm².

surface area of the larger pyramid = 56 cm²

find out the surface area of the smaller pyramid

To proof =

Let us assume that the surface area of the smaller pyramid be x.

as surface area of the larger pyramid is 56 cm²

Two similar pyramid have base area of 12.2 cm² and 16 cm².

by using ratio and proportion

we have

ratio of the base area of the pyramids : ratio of the surface area of the pyramids

$\frac{12.2}{16} : \frac{x}{56}$

x = 12.2 ×56× $\frac{1}{16}$

by solvingthe above terms

we get

x =42.7cm²

Hence the surface area of the smaller pyramid be 42.7cm²

Hence proved

3 0

3 years ago

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Which is true about the graph? Check all that apply

Roman55 [17]

Answer:

what graph?

Step-by-step explanation:

3 0

4 years ago

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The fastest speed recorded for a cheetah is 70 mph. This is 11 mph less than 3 times the fastest running speed for a man. What i

Aleks04 [339]

If we work it through:

70mph is 11mph less than 3 times the fastest running speed for a man.

So 70 + 11 = 81mph is 3 times the fastest running speed for a man.

Can you see where to go from here?

4 0

3 years ago

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The floor of a triangular room has an area of 32 1/2 sq.m. If the triangle’s altitude is 7 172 m, write an equation to determine

sineoko [7]

Answer:

$\frac{(2)A}{h} =b$

b=0.00906m

Step-by-step explanation:

Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation

$A=\frac{bh}{2}$

where

A=area=32.5m^2

h=altitude=7172m

b=base

Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality

$A=\frac{bh}{2} \\\frac{2}{h} A=\frac{bh}{2} \frac{2}{h} \\$