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OlgaM077 [116]
3 years ago
15

As part of a fundraiser, a local charity has sold 5 raffle tickets, with a goal of selling 30 tickets. What percentage of the go

al has been sold? (Round to the nearest tenth of a percent, of necessary.)

Mathematics
2 answers:
AURORKA [14]3 years ago
8 0

Answer:

D. 16.7%

Step-by-step explanation:

We have been given that as part of a fundraiser, a local charity has sold 5 raffle tickets, with a goal of selling 30 tickets. We are asked to find the percentage of the goal that has been sold.

To solve our given problem, we need to find 5 is what percent of 30. To do so, we will divide 5 by 30 and multiply by 100 as:

\text{Percentage of goal that is sold}=\frac{5}{30}\times 100

\text{Percentage of goal that is sold}=\frac{1}{6}\times 100

\text{Percentage of goal that is sold}=16.66666\%

\text{Percentage of goal that is sold}\approx 16.7\%

Therefore, approximately 16.7% of the goal has been sold and option D is the correct choice.

blagie [28]3 years ago
4 0
The answer is 1.5. You multiply 30 x .05
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Answer:

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Step-by-step explanation:

<u>What number</u> <u>divided by</u> <u>-7</u> <u>is equal to</u> <u>-15​</u>

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Multiply -7 to both sides:

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Answer:

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Step-by-step explanation:

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A=P(1+\frac{r}{n})^{nt} ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27

10) Aubrey Daniel's case:

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07

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A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87

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A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69

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