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gregori [183]
3 years ago
7

Define a variable, then write and solve an inequality: Alex and his mother spent at least $130 while shopping for new clothes. A

lex spent $52. How much money did his mother spend?
Mathematics
1 answer:
OLga [1]3 years ago
4 0
52 + x >130
-52 -52
x > 78
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Simplify: -3(4x - 5)
nata0808 [166]

Answer:

8x - 26 \\ -16x - 4 \\ -12x + 15

Step-by-step explanation:

2(4x - 8) - 10

8x - 16 - 10

|_______|

8x - 26

-5x + 8 - 11x - 12

___ ___ _____ ____

___ ____

-16x - 4

-3(4x - 5)

-12x + 15

For the third and first exercises, you just use the Distributive Property, and for the second exercise, all you are doing is combining like-terms.

I am joyous to assist you anytime.

7 0
3 years ago
Find the solution of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B64%5Ctimes%209%7D%20" id="TexFormula
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Step-by-step explanation:

\sqrt{64 \times 9}  \\  \sqrt{8 \times 8 \times 3 \times 3}  \\  =  > 8 \times 3 \\  =  > 24

Hence,Your answer is 24

4 0
3 years ago
Read 2 more answers
You have a new mobile phone. The phone costs £140 and then you pay for a one year contract at £15 per month. How much do you pay
netineya [11]
It is the amount you pay each month times 12
15x12=£180
6 0
3 years ago
(time limit!) what is the volume below?<br><br>A) 112 <br>B) 224 <br>C) 784 <br>D) 896
Radda [10]
To find a volume of a cylinder we use the following formula:
v = \pi {r}^{2} h
Plug in the values:

v = \pi \times  {8}^{2}  \times 14
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8 0
3 years ago
Select all the correct answers.
irina1246 [14]

Operations that can be applied to a matrix in the process of Gauss Jordan elimination are :

replacing the row with twice that row

replacing a row with the sum of that row and another row

swapping rows

Step-by-step explanation:

Gauss-Jordan Elimination is a matrix based way used to solve linear equations or to find inverse of a matrix.

The elimentary row(or column) operations that can be used are:

1. Swap any two rows(or colums)

2. Add or subtract scalar multiple of one row(column) to another row(column)

as is done in replacing a row with sum of that row and another row.

3. Multiply any row (or column) entirely by a non zero scalar as is done in replacing the row with twice the row, here scalar used = 2

6 0
3 years ago
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