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Stolb23 [73]
3 years ago
9

What is the solution to w-9 1/2=15 A)5 1/2 B 6 1/2 C) 241/2 D) 23 1/2

Mathematics
2 answers:
erik [133]3 years ago
8 0
The answer is C. 241/2
cupoosta [38]3 years ago
4 0
The answer is C. 24 1/2
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I need the answer for 6
Gnoma [55]
ME AGAIN!!! You should just let me do your homework from now on lol.


So, you have 4 red, 3 green and 1 yellow. Add all of those numbers together, you should get 8. How many green did you start with? You started with 3. So your answer is either 3:8, 3/8, or 3 to 8.


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5 0
3 years ago
X + 43 = 50 what does "x" equal?? EXPLAIN
kakasveta [241]
Hey there!

43 + 7 = 50

so x = 7

Hope this helps
Have a great day (:
4 0
3 years ago
Read 2 more answers
A principal of 750$ is invested in an account at 9% per year simple interest. What is the account total after 5 years
balandron [24]
Hi there
The formula of the future value of simple interest is
A=p (1+rt)
A future value?
P principle 750
R interest rate 0.09
T time 5years
So
A=750×(1+0.09×5)
A=1,087.5

Good luck!
4 0
3 years ago
The boat travels x miles per hour from one island to another island in 2.5 hours. The boat travels 5 miles per hour faster on th
notka56 [123]
The speed to the island is x. The speed to return is x+5.

The distance is the same so, 2.5 multiplied by x = 2×(x+5).

It took 2.5 hrs to get there and 2 hrs to return. Now all we have to do is solve.

 2.5*x = 2x + 10

 .5x = 10
x=20

 Therefore, the distance between islands is 2.5 × 20 = 50 miles.

hope this helps!

6 0
3 years ago
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
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