Someone please help. It is easy
1 answer:
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Answer:
The solution sets are 1, 5 and 7
Step-by-step explanation:
Given the polynomial function,
f(x) = x³-13x²+47x-35
If 1 is a zero function of f(x), according to factor theorem, the linear equation x-1 is a factor of the polynomial.
To get the other solution set, we will have to divide the polynomial function by x-1 and factorize the quotient function.
Factorising the resulting quotient function.
Q(x) = x²-12x+35 = 0
= x²-5x-7x+35 = 0
= x(x-5)-7(x-5) = 0
(x-5)(x-7) = 0
x-5 = 0 and x-7 = 0
x = 5 and 7
