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tensa zangetsu [6.8K]
4 years ago
15

Simplify 4 to the third power and 2 to the sixth power.

Mathematics
2 answers:
Viefleur [7K]4 years ago
6 0

Answer:

4^3 = 4x4x4=64

2^6=2x2x2x2x2x2=64

dem82 [27]4 years ago
3 0

Answer:

4^3=64. 2^6=64

Step-by-step explanation:

4X4X4=64

2X2X2X2X2X2=64

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F(x) = 3x, g(x) = 1/3f(x). Find g(0)
schepotkina [342]

Answer:

f(1/3)=3 try that its probably right

4 0
3 years ago
the length of a rectangular poster is 10 inches longer than the width. if the perimeter of the poster is 124 inches, what is the
Jlenok [28]

The formula for the perimeter is 2L + 2W.

Since we know that L=10+W, we can substitute this into the equation.

2(10+W) +2W=124

20+2W + 2W=124

4W +20 = 124

4W=104

W=26

Therefore, the width is 26 inches.

6 0
3 years ago
Please answer this question and I will give you brainliest !! Show your work !!
Diano4ka-milaya [45]

Answer:

Initiation fee:

$400

Monthly fee:

$10

Step-by-step explanation:

First, let's start by calculating the monthly fee.

Over a period of 5 months (5 -> 10 months), the member paid 50 dollars more.  We can divide this number by 5 to find the monthly fee. The monthly fee is $10.

Now, we can find the initiation fee. After 5 months with the gym, the member had spent $450. As we already know, $50 is the price for 5 months, so the member paid $50 in monthly fees.

We subtract $50 from the total cost ($450) to find that the initiation fee is $400.

Now, we can write the equations for each statement.

<em>Let m represent the monthly fee and i represent the initiation fee:</em>

"At the end of 5 months, a member had paid a total of $450"

5m + i = 450

"At the end of 10 months, she had paid a total of $500.

You could use 2 equations for this statement:

10m + i = 500

OR, if you use the above facts to calculate the fact that there was a $50 increase from those five months, and exclude the initiation fee and the previous five months:

5m = 50

Hope this helps!

4 0
3 years ago
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
3
Nastasia [14]

Hey there! I'm happy to help!

Lines that are parallel have the same slopes because they are increasing or decreasing at the same rate and therefore will never bump into each other.

We see that y=2 has a slope of 0 because there is no x that we can see in the equation. This is just a flat line.

If the line we are looking for is flat; it stays at the same y-value the entire time. We see that  the y-value for this line of ours is -6. Therefore, the answer is C. y=-6.

I hope that this helps! Have a wonderful day!

3 0
4 years ago
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