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Ksivusya [100]
3 years ago
7

3

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0

Hey there! I'm happy to help!

Lines that are parallel have the same slopes because they are increasing or decreasing at the same rate and therefore will never bump into each other.

We see that y=2 has a slope of 0 because there is no x that we can see in the equation. This is just a flat line.

If the line we are looking for is flat; it stays at the same y-value the entire time. We see that  the y-value for this line of ours is -6. Therefore, the answer is C. y=-6.

I hope that this helps! Have a wonderful day!

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State if the given binomial is a factor of the given polynomial <br>(10x^3+95^2+40x-45)÷(x+9)​
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write it neatly

Step-by-step explanation:

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Plz help math #5 questions
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Okay , wheres the questions at tho...?


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Show your work with long division please
Naya [18.7K]

Answer:

<h3>   __</h3><h3>0.63</h3>

Step-by-step explanation:

7/11 = no, add 0

70/11 = 6, so 0.6, remainder is 4, add 0

40/11 = 3, so 0.03, remainder is 7, add 0

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<h3>The answer is 0.63 bar notation on both 6 and 3</h3>
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3 years ago
What is 10^-10 in decimal form?
S_A_V [24]
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6 0
3 years ago
A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range
maria [59]

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, \hat p.

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Given:

n = 150

\hat p = 0.68

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

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Thus, the reasonable range for the population mean is (61%, 75%).

5 0
3 years ago
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