<em>a = 30°</em>
<em>b = 70°</em>
<em>c = 80°</em>
- Step-by-step explanation:
<em>Hi there ! </em>
<em />
<em>a ; b ; c = angles</em>
<em>a + b + c = 180°</em>
<em>b + c = 5a</em>
<em><u>replace (b + c)</u></em>
<em>a + (b + c) = 180</em>
<em>a + 5a = 180</em>
<em>6a = 180</em>
<em>a = 30°</em>
<em />
<em>b + c = 180 - a</em>
<em>b + c = 150</em>
<em>c = b + 10</em>
<em><u>replace c</u></em>
<em>b + (b + 10) = 150</em>
<em>2b = 150 - 10</em>
<em>2b = 140</em>
<em>b = 70°</em>
<em>c = b + 10</em>
<em>c = 80°</em>
<em>Good luck !</em>
B and A is the correct answers
A right triangle has two legs and a hypotenuse
a = shorter leg
b = longer leg
c = hypotenuse
We know b-a=4, or b = a+4
The Pythagorean theorem states:
a2 + b2 = c2
a2 + (a+4)2 = c2
a2 + (a+4)2 = 80
a2 + a2 + 8a + 16 = 80
Combine terms
2a2 + 8a - 64 = 0
Divide by 2
a2 + 4a - 32 = 0
Factor
(a+8)(a-4) = 0
a = 4, -8
We throw out the -8 solution because we can't have a negative measure.
So a = 4
b = 8
c = √80 = 4√5
The legs are 4 and 8.
<span><span>1.
</span>The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
Thurs 2/5 were occupied
=> 6/20 = 0.3
=> 20 * 0.3 = 6 boxes
Friday 2/4 were occupied
=> 7/20 = 0.35
=> 20 * 0.35 = 7 boxes
Saturday 8/10 were occupied.
=> 10/20 = 0.5
=> 20 * .5 = 10 boxes
Thus, during Saturday has the most number of occupied boxes.</span>
Answer:
Step-by-step explanation:
m
=
7.3
π
=
22.93
(rounded to 2 decimal places)
Explanation:
Multiply both sides by
π
m
π
×
π
=
7.3
×
π
m
=
7.3
×
π
m
=
7.3
×
3.14159
...
.
m
=
22.9336
...
.
For
π
, you can use your calculator value as I have done here, or you can use
3.14
or
3.142
or
22
7
You will get slightly different answers each time.
