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3 years ago

6

4r−3=3(3r+4) what is the answer

1 answer:

DaniilM [7]3 years ago

8 0

r=−3 hope i helped and please mark as brainliest! :)

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Which expression is equal to 9(6 - t)? How do you know?

Gnesinka [82]

Answer:

54-9t

Step-by-step explanation:

multiply the 9 with 6 and multiply 9 with the t which has an invisible 1

4 0

2 years ago

Read 2 more answers

Monica says,"if 4 bottles cost $10, then 2 bottles cost $5 + $20." Is Monica correct? Explain

Igoryamba

Answer:

Monica is not correct.

Step-by-step explanation:

First of all, if 4 bottles only cost $4, then how would only 2 cost more? (She said the two bottles would be $25, which doesn’t make sense.)

8 0

2 years ago

What is 8x + -13x I just want to see if the answers are as quick as it says it is

Dafna1 [17]

- 5x.
In case you actually want to know how I got it:
the question is just saying "8x - 13x".
8 - 13 = -5

4 0

2 years ago

Read 2 more answers

INSCRIBED ANGLES PLZ HELP ASAP

Taya2010 [7]

The answer is 46°.

The measure of an inscribed angle is equal to (1/2) the measure of the intercepted arc.

That means that, since ADC is 23 degrees, doubling that gives you 46 degrees, the measure of the intercepted arc.

Central angles are equal to the measure of the intercepted arc, which in this case is the same arc we just calculated.

Therefore it's 46.

4 0

2 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

2 years ago