Question

Al saves pennies. He agreed to give 3/7 of his pennies to Bev if she would give 3/7 of what she got from Al to Carl and if Carl in turn would give 3/7 of what he got from Bev to Dani.​ Bev, Carl, and Dani agreed and Dani received 216 pennies. How many pennies did Al have​ initially?

Answer 1

Answer:

2744 pennies.

Step-by-step explanation:

Let x represent the number of pennies Al have initially.

We have been given that Al agreed to give 3/7 of his pennies to Bev, so number of pennies Bev will get would be $\frac{3}{7}x$.

We are also told that Bev gave 3/7 of what she got from Al to Carl, so number of pennies that Carl will get would be $\frac{3}{7}x\cdot \frac{3}{7}=\frac{9}{49}x$.

Further, Carl gave 3/7 of what he got from Bev to Dani, so number of pennies that Dani will get would be $\frac{9}{49}x\cdot \frac{3}{7}=\frac{27}{343}x$.

We are also told that Dani received 216 pennies. Now, we will equate 216 to $\frac{27}{343}x$ and solve for x as shown below:

$\frac{27x}{343}=216$

$\frac{27x}{343}*343=216*343$

$27x=74088$

$\frac{27x}{27}=\frac{74088}{27}$

$x=2744$

Therefore, Al have 2744 pennies initially.