Y = mx + b is the slope-intercept form of the equation of a line,
where m = slope, and b = y-intercept.
In problems 1 and 3, your equations are written in the y= mx + b form, so you can read the slope and y-intercept directly.
1.
m = -5/2
b = -5
3.
m = -1
b = 3
5.
For problem 5, you need to solve for y to put the equation
in y = mx + b form. Then you can read m and b just like we did
for problems 1 and 3.
4x + 16y = 8
16y = -4x + 8
y = -4/16 x - 8/16
y = -1/4 x - 1/2
m = -1/4
b = -1/2
QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer: 60, but I got other answers to but 60 was my first.
sorry if wrong.
Step-by-step explanation:
Answer:
-9
Step-by-step explanation: