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4 years ago

I would appreciate if someone helped. i don't understand

Mathematics

2 answers:

Korolek [52]4 years ago

8 0

Answer:

44 units.

Step-by-step explanation:

Dilation is the transformation of an image's size by a scale factor.

The scale factor is given 2.

The rectangle has a perimeter of 22.

22 × 2 = 44

The perimeter for the resulting image is doubled by the scale factor of 2.

sleet_krkn [62]4 years ago

5 0

Answer:

44 units

Step-by-step explanation:

When you perform a dilation on a figure, all of the side lengths of the figure get multiplied by the scale factor. This means that the perimeter is also multiplied by that scale factor. Since in this case that scale factor is 2, the new perimeter is 22*2=44 units. Hope this helps!

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George was given 11 grams of medicine, but the full dose is supposed to be 25 grams. What percent of his full dose did George re

Bess [88]

Answer: George receive 44 % of his full dose .

Step-by-step explanation:

Given : The amount for full dose : 25 grams

The amount received by George = 11 grams

Now, the percent of his full dose received by George :-

$\dfrac{\text{Dose taken by George}}{\text{Full dose}}\times100$

$=\dfrac{11}{25}\times100=44\%$

Hence, George receive 44 % of his full dose .

8 0

3 years ago

) f) 1 + cot²a = cosec²a

notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

$\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}$

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

$\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}$

Another identity is:

$\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}$

Therefore:

$\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}$

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

$\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}$