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3 years ago

What is eight fifths reduced to lowest terms?

Mathematics

1 answer:

gladu [14]3 years ago

4 0

1 3/5

(8-5=3, you have one set of 5/5 with 3 left over so 1 3/5)

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The members of the city cultural center have decided to put on a play once a night for a week. Their auditorium holds

fgiga [73]

A) At $3,300 for 600 seats, the average price per seat is 3300/600 = $5.50. The mix of tickets that results in that average can be found using an X diagram as shown below. The numbers on the right are the differences along the diagonals. When they are multiplied by 2, they add to 600. This shows that the required sales for revenue of $3,300 are
200 adult tickets
400 student tickets

b) When 3 student tickets are sold for each adult ticket, the average seat price is
(3*$4.50 +7.50)/4 = $5.25
Then the shortfall in revenue is ...
$3,300 -480*$5.25 = $780

Hope I was able to help!<3 mark brainly I would appreciate it!:)

8 0

3 years ago

Solve for x in the triangle. Round your answer to the nearest tenth.

joja [24]

Answer:

Step-by-step explanation:

label sides adjacent h and o

sin(30) times 12 = 6 = 10

8 0

2 years ago

REALLY NEED HELP PLEASE!!!

qwelly [4]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

the answer is

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

which would give you

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes