Question

Lim t—>0 1-cos(2t) / sin^2 (11t)

Answer 1

Answer:

2/121

Step-by-step explanation:

Hello,

Hôpital's rule will help here.

$\forall t \in \mathbb{R}^*\\\\f(t)=1-cos(2t)\text{ *** f is differentiable}\\f'(t)=2sin(2t)\\f''(t)=4cost(2t)\\f''(0)=4 \\ \\g(t)=sin^2(11t)\text{ *** g is differentiable}\\g'(t)=2sin(11t)\times 11 \times cos(11t)=2\times 11 sin(11t)cos(11t)\\\\g''(t)=2\times 11 (11cos^2(11t)-11sin^2(11t))\\g''(0)=2\times 11^2$

So the limit is 4/(2*121)=2/121

Thanks