In the normal distribution, values in the distribution being measured are close to the mean (high or low values are infrequently
2 answers:
You might be interested in
Answer:
(3,2)
Step-by-step explanation:
I graphed the two lines using a graphing tool. The lines intercept at (3,2). Therefore, the solution to the system is (3,2).
X-y=5
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula
for
ay^2+by+c=0
for 1y^2+5y-3.36
y=-2.5+/-3.1
y=5.6 or 0.6
sub back
x=y+5
so
x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
answer is 0.6 and 5.6
xy=3.36
add y to both sides on first
x=5+y
sub that in other eqation
(5+y)y=3.36
expand
y^2+5y=3.36
minus 3.36 both sides
y^2+5y-3.36=0
use quadratic formula
for
ay^2+by+c=0
for 1y^2+5y-3.36
y=-2.5+/-3.1
y=5.6 or 0.6
sub back
x=y+5
so
x=10.6 or 5.6
the numbers are either 10.6 and 5.6 or 0.6 and 5.6
wait,but 10.6 and 5.6 don't multiply to get 3.36 so that is an extrainiesous answer
answer is 0.6 and 5.6