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3 years ago

Please answer ASAP!!! Will give branliest!!!

Mathematics

1 answer:

Anarel [89]3 years ago

8 0

We know that the perimeter of a rectangle is 2l+2w

24=2y+2x

Subtract 2x on both sides (we are isolating y)

24-2x=2y

Divide 2 on both sides

Therefore, y=12-x

Some possible values using this equation..

y=8

x=4

Hope this helped :)

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Three security cameras were mounted at the corners of a triangular parking lot. Camera 1 was 106 ft from camera 2, which was 133

Harrizon [31]

Correct Answer:
Option C. Camera 2

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So the largest side of the triangle is the side between camera 1 and camera 3. So the camera opposite to this side will have to cover to greatest angle. The camera opposite to this side is Camera 2. This scenario is also shown in figure below.

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3 years ago

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makvit [3.9K]

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3 years ago

You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl

gtnhenbr [62]

Answer:

maximum difference of radii = $(r-R)=\frac{1}{2\pi ^{2}}$

Step-by-step explanation:

We know that area of circle is given by

$A=\pi \times (radius)^{2}$

For circle with radius 'r' we have

$A_{1}=\pi \times (r)^{2}$

For circle with radius 'R' we have

$A_{2}=\pi \times (R)^{2}$

Now according to given condition we have

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$\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}$

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4 years ago

What point is a solution for the linear inequality x−3y≥4?

alexgriva [62]

Answer:

(4,0)

Step-by-step explanation:

when x−3y≥4 is graphed it goes through the point (4,0)

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3 years ago