By solving the equations x+2y=5, 4x-12y=-20 through elimination or substitution method we will get the value of x=1 and y=2.
Given two equations x+2y=5 and 4x-12y=-20.
We are required to solve the equations through elimination and substitution method.
Firstly we will solve the equations through elimination method.
x+2y=5-------------1
4x-12y=-20--------2
Multiply the equation 1 by 4 and then subtract the equation 2 from equation 1.
4x+8y-4x+12y=20+20
20y=40
y=2
Use the value of y in 1
x=5-2*2
x=5-4
x=1
From substitution method.
First find the value of x from first equation in terms of y.
x=5-2y-----4
Now put this value in second equation to get the value of y.
4(5-2y)-12y=-20
20-8y-12y=-20
20-20y=-20
-20y=-40
y=2
Put the value of y in equation 4.
x=5-2y
x=5-2*2
x=5-4
x=1
Hence by solving the equations x+2y=5, 4x-12y=-20 through elimination or substitution method we will get the value of x=1 and y=2.
Learn more about equations at brainly.com/question/2972832
#SPJ1
I think its either 1% or 2%
Answer:
4/15
Step-by-step explanation:
To multiply fractions you multiply the numerator together and the denominators together.
So:
numerators: 1 x 4 = 4
denominators: 3 x 5 = 15
The answer is 4/15
Advanced mathematical concepts glencoe answers indeed.
