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Flura [38]
3 years ago
12

I don't even know where to start on this problem?

Mathematics
1 answer:
velikii [3]3 years ago
7 0
I think you have to count 85 and go down like 85 86 87so the answer is 15
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Of her book on Tuesday, and of her book on Wednesday,
Step2247 [10]

Answer: 9/10 of the book.

Step-by-step explanation:

1. Convert all of the fractions to have a common denominator. 6, 5, and 3 are all multiples of 30, so we can convert the fractions to 30ths.

1/6 = 5/30

2/5 = 12/30

1/3 = 10/30

2. Add the fractions together to find the whole amount of the book Joyce has read.

5/30 + 12/30 + 10/30 = 27/30

3. Simplify

27/30 -> 9/10

5 0
3 years ago
Read 2 more answers
The angles of a triangle are described as follows: angle a is the largest angle; it measure is twice the measure of Angle b. The
nikklg [1K]

Answer:

Angle A = 102°

Angle B = 51°

Angle C = 27°

Step-by-step explanation:

angle A = 2b

angle B = b

angle C = 1/3 b + 10

Angle A + Angle B + Angle C = 180

2b + b + 1/3 b + 10 = 180

3 1/3 b + 10 = 180

10/3 b = 170

b = 51

a = 2b = 102

c = 1/3 b + 10 = 1/3 (51) + 10 = 17 + 10 = 27

4 0
3 years ago
A single tree produces about 2.6 × 10² lb of oxygen each year. The Amazon rainforest has about 3.9 X 10^11 trees.
Ymorist [56]
(2.6\times10^2) \times (3.9\times10^{11}) = 1.014\times10^{14}

1.014\times10^{14} <---How much is produced by all the trees in a year. 
They want how much each day so divide by 365


\frac{1.014\times10^{14}}{365} = 2.77808\times10^{11}
2.77808\times10^{11} <---answer per day

6 0
2 years ago
Read 2 more answers
If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b
Readme [11.4K]

Answer:

  • Exact distance = 90\sqrt{2} feet
  • Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0
2 years ago
HELPP!! PLEASE ITS DUE SOON
Debora [2.8K]

Answer:

100%

Step-by-step explanation:

3 0
3 years ago
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