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mixas84 [53]
2 years ago
5

A neon light flashes five times every 10 seconds. Show that the light flashes 43 200 times in one day.

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
4 0

1 day = 24 hours

1 hour = 60 minutes

1 minute = 60 seconds

60 seconds x 60 minutes = 3,600 seconds per hour

3,600 seconds per hour x 24 hours = 86,400 seconds per day.

The light flashes 5 times every 10 seconds:

5 flashes / 10 seconds = 1 flash every 2 seconds

86,400 seconds / 2 seconds = 43,200 flashes per day.

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4 3/8+ 2 7/12 <br> Alguém sabe a resposta
Nata [24]

Answer:

6 23/24

Step-by-step explanation:

First, find the least common factor of 8 and 12, the denominators.

8 16 24

12 24

24, is now the current denominnator,

8x 3 = 24

Now you go do it to the numerator, 3 x 3 = 9

9/24 + ?

Now, 12 x 2 = 24, do it to the numerator, 7 x 2 = 14

4 9/24 + 2 14/24

Now add the front numbers to make 6, than add the numerators and keep the denominator.

6 23/24, since you can not simplify this fraction, this is the answer.

6 0
2 years ago
Which expression represents the product of an unknown number and 19?
Galina-37 [17]
I would go with D. Hope that helps :)
7 0
3 years ago
Read 2 more answers
Find the midpoint of the line segment that has endpoints at (10,8) (-3,-10)
dem82 [27]

Hey there! :)

Answer:

(3.5, -1).

Step-by-step explanation:

Use the midpoint formula to solve this problem:

(x_m, y_m) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Plug in the coordinates given:

(\frac{10-3}{2}, \frac{8-10}{2})

Simplify:

(\frac{7}{2}, \frac{-2}{2})

Therefore, the coordinates of the mid-point are:

(3.5, -1).

7 0
3 years ago
45% of the 647 students at Royal Oak High attended the football game. How many students did not attend?
Lostsunrise [7]
First multiply
.45*647= 291.15
291.15 is the number of people that attended 
subtract 291.15 from 647 and you get 355.85 wait.. but that's not possible so just round it so the answer to your question is 355 people did not attened
3 0
3 years ago
Read 2 more answers
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{30732 - 30393}{472.81}

Z = 0.72

Z = 0.72 has a pvalue of 0.7642.

X = 30054

Z = \frac{X - \mu}{s}

Z = \frac{30054 - 30393}{472.81}

Z = -0.72

Z = -0.72 has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

4 0
3 years ago
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