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bulgar [2K]
3 years ago
8

Mary is thinking of three consecutive even integers, x, y, and z. Three times the value of z exceeds half the value of x by 37.

What is the value of x?
Mathematics
1 answer:
Naya [18.7K]3 years ago
6 0

Answer:

  x = 10

Step-by-step explanation:

You know z = x+4, so ...

  3z -x/2 = 37 . . . . . . . . the given relation

  3(x +4) -x/2 = 37 . . . . substituting for z

  5/2x +12 = 37 . . . . . . .eliminate parentheses and simplify

  5/2x = 25 . . . . . . . . . . subtract 12

  x = 10 . . . . . . . . . . . . . multiply by 2/5

_____

<em>Check</em>

3z = 3·14 = 42

x/2 = 10/2 = 5

42 exceeds 5 by 37 . . . . true

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Read 2 more answers
Surface Area of Cylinder=2πrh+2πr2
Alex

  • Find the surface area when r is 8 inches and h is 8 inches.

\qquad A. 160π in²

\qquad B. 154π in²

\qquad C. 288π in²

\qquad D. 256π in² ☑

We are given –

\qquad ⇢Radius of cylinder , r = 8 inches

\qquad⇢ Height of cylinder, h = 8 inches.

We are asked to find surface area of the given cylinder.

Formula to find the surface cylinder given by –

\bf \star \pink{ Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2 }

Now, Substitute given values –

\sf  \twoheadrightarrow  Surface\: Area_{(Cylinder)} = 2\pi rh +2\pi r^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 2 \pi \times 8 \times 8 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2 \pi \times 8^2 + 2\pi \times 8^2

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)} = 2\pi \times 64 +2\pi \times 64

\sf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  =128 \pi + 128\pi

\purple{\bf  \twoheadrightarrow Surface\: Area_{(Cylinder)}  = 256\pi \: in^2 }

  • Henceforth,Option D is the correct answer.

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2 years ago
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