Yes you can. The quadrilateral that you would get is called parallelogram. It has 2 paris of parallel lines. and 2 pairs of equal angles. one pair is angles that are less than 90 degrees and other one is where 2 angles are greater than 90 degrees each. Therefore there isnt any right angle there and you got yourself quadrilateral. of these 2 parallel lines are of equal lenght than you get something called rhombus.

8 0

3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are without replacement.

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

How to find equation of line passing through the points (x,y)

DochEvi [55]

First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.

Linear function has a form of,

$y=mx+n$

Then calculate the slope m using the coordinates of two points. Let say A(x1, y1) and B(x2, y2),

$m=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{y_2-y_1}{x_2-x_1}$

Now pick a point either A or B and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point A.

$y_1=mx_1+n$

From here you solve the equation for n,

$y_1=mx_1+n\Longrightarrow n=y_1-mx_1$

So you have slope m and variable n therefore you can write down the equation of the line,

$f(x)=m_{slope}x+n_{variable}$

Hope this helps.

r3t40

3 0

3 years ago

Choose all that rearrange the formula correctly.If

Sonbull [250]

Answer:

I sure hope none is an answer because none of these work!

Step-by-step explanation:

C = 59 (F - 32)

(C/59) = F - 32

F = C/59 + 32

So no :(

m = x + y + z3

y = m - x - z3

So no :((

s = r^2 - 1

r = sqrt(s+1)

So no :000

A = 12(a+b)

A = 12a + 12b

12b = A - 12a

b = A/12 - a

So no :00(((

m = x + y^2

y = sqrt (m-x)

AND no :|

5 0

3 years ago