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3 years ago

Find the area and the circumference of a circle with diameter 9 yards using the value 3.14 for pi

1 answer:

5 0

Area of circle = pi r^, (r)radius is half the diameter so 9÷2=4.5 so in this scenario it would be 3.14×4.5^
3.14×4.5×4.5=63.6

circumference of circle= diameter×pi (3.14)
so 9×3.14=28.3

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Weight gain during pregnancy. In 2004, the state of North Carolina released to the public a large data set containing informatio

pychu [463]

Answer:

1. B. H0: μ1−μ2=0, HA: μ1−μ2≠0

2. z=1.2114

3. P-value=0.2257

4. Do not reject H0

Step-by-step explanation:

We have to perfomr an hypothesis test to see if there is strong evidence that there is a significant difference between the two population means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2\neq0$

Being μ1 the mean average gain for younger mothers and μ2 the mean average gain for mature mothers.

(NOTE: we are comparing means, not proportions, as it is the random variable is the weight gain).

As we are claiming "strong evidence", the level of significance will be 0.01.

For younger mothers, the sample size is n1=840, the sample mean is 30.7 and the sample standard deviation is s1=14.91.

For mature mothers, the sample size is n2=132, the sample mean is 29.15 and the sample standard deviation is s2=13.46.

The difference between means is

$M_d=\mu_1-\mu_2=30.7-29.15=1.55$

The standard error of the difference between means is

$s_M=\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}=\sqrt{\dfrac{14.91^2}{840}+\dfrac{13.46^2}{132}}=\sqrt{ 0.2647+1.3725}=\sqrt{1.6372}\\\\\\s_M=1.2795$

Then, the statistic can be calculated as:

$z=\dfrac{M_d-(\mu_1-\mu_2)}{s_M}=\dfrac{1.55-0}{1.2795}=1.2114$

The P-value for this z-statistic in a two tailed test is:

$P-value=2P(z>1.2114)=0.2257$

As the P-value is greater than the significance level, the null hypothesis failed to be rejected.

There is no enough evidence to claim that the real average weight gain differs from mature and youger mothers.

5 0

3 years ago

Jell E. Bean owns the local frozen yogurt shop. At her store, customers themselves a bowl of frozen yogurt. Jell E. Bean charges

uysha [10]

Answer:

Step-by-step explanation:

Unit rate = $32/(5 pounds) = $6.40/pound

[You can convert that to smaller units:

$6.40/pound × (1 pound)/(16 ounces) = $0.40/ounce]

:::::

Cost = (number of pounds) × $6.40/pound

:::::

12 pounds × $6.40/pound = $76.80

6 0

2 years ago

Evaluate the expression. P(9, 3) · P(5, 4)

boyakko [2]

Answer:

$P(9,3) *P(5,4)$

And if we use the permutation formula given by:

$nPx = \frac{n!}{(n-x)!}$

And replacing we got:

$\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520$

Step-by-step explanation:

For this problem we want to find the following expressionÑ

$P(9,3) *P(5,4)$

And if we use the permutation formula given by:

$nPx = \frac{n!}{(n-x)!}$

And replacing we got:

$\frac{9!}{6!} \frac{5!}{4!}= 504*5 = 2520$

6 0

3 years ago

Which solid has a greater volume

Triss [41]

Answer:

The volume of cylinder and the volume of a cone, have equal volume measurements. So, the answer is C).

Step-by-step explanation:

Cylinder:

-Use the formula for the volume of a cylinder. Use both the radius and height for the formula in order to solve and get the volume:

$V = \pi r^2 h$

$V = \pi 2^2 6$

-Solve:

$V = \pi 2^2 6$

$V = \pi \times 2^2 \times 6$

$V = \pi \times 4 \times 6$

$V = \pi \times 24$

$V = 24\pi \approx 75.39$

--------------------------------------------------------------------------------------------------------

Cone:

-Use the formula for the volume of a cone and the radius and height for the formula and solve the formula to get the volume:

$V = \frac{1}{3} \pi r^2h$

$V = \frac{1}{3} \pi 3^28$

-Solve:

$V = \frac{1}{3} \pi 3^28$

$V = \frac{1}{3} \times \pi \times 3^2 \times 8$

$V = \frac{1}{3} \times \pi \times 9 \times 8$

$V = \frac{1}{3} \times \pi \times 72$

$V = \frac{1}{3} \pi \times 72$

$V = 24\pi \approx 75.39$

-So, according to the volume of a cylinder and the volume of a cone, They both have the same volume.

Cylinder: $75.39$ $ft^3$

Cone: $75.39$ $ft^3$

5 0

3 years ago

What is the number 731000934030 written in standard form

NARA [144]

7.31000934030 x 10^11

7 0

3 years ago

Read 2 more answers