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stepan [7]
3 years ago
11

The population of a town increases at a rate of 5% every year. The population of this town was 10,400 in 2017. What will the pop

ulation of the town be in 2020?
Mathematics
1 answer:
galben [10]3 years ago
6 0

Answer:

The population of the town in 2020  will approx. be 12,039.

Step-by-step explanation:

The initial population in the year 2017 = 10,400

Increase in population every yea r  =  5%

Now, 5% of 10, 400 = \frac{5}{100} \times 10, 400 = 520

Hence, the population in the year 2018 = 10,400 + 520 = 10,920

Now, in the year 2019

5% of 10, 920 = \frac{5}{100} \times 10, 920 = 546

Hence, the population in the year 2019 = 10,920 + 546 = 11,466

Now, in the year 2020

5% of 11,466 = \frac{5}{100} \times 11,466 = 573.3

or, the population in the year 2020 = 11,466  + 573.3 = 12,039.3

The population of the town in 2020  will approx. be 12,039.

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3 years ago
A bank pays 5% interest compounded annually. What principal will grow to $12,000 in 10 years.
makvit [3.9K]
<h3>Answer: 7366.96 dollars</h3>

========================================================

Use the compound interest formula:

A = P(1+r/n)^(n*t)

where in this case,

A = 12000 = amount after t years

P = unknown = deposited amount we want to solve for

r = 0.05 = the decimal form of 5% interest

n = 1 = refers to the compounding frequency (annual)

t = 10 = number of years

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Plug all these values into the equation, then solve for P

A = P(1+r/n)^(n*t)

12000 = P(1+0.05/1)^(1*10)

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12000 = P(1.62889462677744)

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<h3>Rate of change</h3>

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Hence the rates that are equivalent to this rate is 90 pages/hr

Learn more on rate here: brainly.com/question/119866

6 0
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4 0
3 years ago
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