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Bezzdna [24]
3 years ago
8

A certain dishwasher uses 29 kilowatts of energy per hour.if the dishwasher was used 156 hours last year how many kilowatts of e

nergy did the dishwasher use last year?
Mathematics
1 answer:
hram777 [196]3 years ago
6 0
156 x 29 = 4524 kilowatts of energy
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Katie walks 1/2 mile in 1/6 hour. what is her unit rate of speed
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Katie travels at 0.05 mi/ min
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Please help quickly !
Ira Lisetskai [31]

Answer:

75 - 52.5 = x

Step-by-step explanation:

\because 52.5 + x = 75\\\therefore x = 75 - 52.5\\\therefore 75 - 52.5 = x \\

is the correct answer.

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Please help me it says What kind of triangle makes the Pythagorean theorem true?what angle does it need to have?
Levart [38]
<h3>Answer:</h3>

right triangle

<h3>Step-by-step explanation:</h3>

The sides of a right triangle in a simple way, so that if the lengths of any two sides are known the length of the third side can be found.

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2 years ago
Over a 24-hour period, the tide in a harbor can be modeled by one period of a sinusoidal function. The tide measures 5.15 ft at
Crazy boy [7]

Answer:

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Step-by-step explanation:

5 0
2 years ago
What the second answer ​
Debora [2.8K]

Answer:

1. y' = 3x² / 4y²

2. y'' = 3x/8y⁵[(4y³ – 3x³)]

Step-by-step explanation:

From the question given above, the following data were obtained:

3x³ – 4y³ = 4

y' =?

y'' =?

1. Determination of y'

To obtain y', we simply defferentiate the expression ones. This can be obtained as follow:

3x³ – 4y³ = 4

Differentiate

9x² – 12y²dy/dx = 0

Rearrange

12y²dy/dx = 9x²

Divide both side by 12y²

dy/dx = 9x² / 12y²

dy/dx = 3x² / 4y²

y' = 3x² / 4y²

2. Determination of y''

To obtain y'', we simply defferentiate above expression i.e y' = 3x² / 4y². This can be obtained as follow:

3x² / 4y²

Let:

u = 3x²

v = 4y²

Find u' and v'

u' = 6x

v' = 8ydy/dx

Applying quotient rule

y'' = [vu' – uv'] / v²

y'' = [4y²(6x) – 3x²(8ydy/dx)] / (4y²)²

y'' = [24xy² – 24x²ydy/dx] / 16y⁴

Recall:

dy/dx = 3x² / 4y²

y'' = [24xy² – 24x²y (3x² / 4y² )] / 16y⁴

y'' = [24xy² – 18x⁴/y] / 16y⁴

y'' = 1/16y⁴[24xy² – 18x⁴/y]

y'' = 1/16y⁴[(24xy³ – 18x⁴)/y]

y'' = 1/16y⁵[(24xy³ – 18x⁴)]

y'' = 6x/16y⁵[(4y³ – 3x³)]

y'' = 3x/8y⁵[(4y³ – 3x³)]

6 0
2 years ago
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