How do I solve this?
2 answers:
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Answer: a.) 72 of each type of animal, for a total of 216
b.) 16 grown cats, 4 kittens
Step-by-step explanation:
part a. It's a distribution (division) problem. The same number of each animal is distributed over some unknown number of troughs, but the total number of troughs adds up to 69. ( I hate to give this all away, as its a brilliant problem! )
Number of troughs for each animal type is How many needed by the number of animals per trough:
h/2 + c/3 + p/8 = 69
Since we are given "the same number of horses, cows and pigs" we can substitute "x" for all.
Get a common denominator. 24 would work, 48 also.
24x + 16x + 6x = 3372
46x = 3372 x = 72
Proof: calculate the number of each kind of trough
Horses 72/2 = 36, Cows 72/3 = 24 Pigs 72/8 = 9 36+24+9 = 69
part b. 5c + 3k = 92, c + k = 20 Rearrange to get a value for c to substitute.
c = 20-k 5(20-k) +3k =92 Distribute and solve
100 - 5k + 3k = 92 becomes -2k = -8 so k = 4 Substitute into the original
c + 4 = 20 becomes c=20-4, so c = 16
Proof: 5c +3k = 92 Substitute values 5(16) + 3(4) = 92 80 + 12 = 92
Answer:
Erwin have 1 gallons of lemonade left
Step-by-step explanation:
<u><em>Erwin had 2 5/12 gallons of lemonade. He spilled 11/12 gallon of lemonade. How much lemonade dose he have left? Write in simplest form</em></u>
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All we need to do is to subtract 11/12 from 2 5/12. But to do this, we will convert 2 5/12 to improper fraction
converting 2 5/12 to improper fraction yields : 29/12
Lemonade have left = Total lemonade - lemonade spilled
= 29/12 - 11/12
= 18/12
Lemonade have left =18/12
But we can reduce 18/12 to its lowest term
18÷6/ 12÷6 = 3/2
Lemonade have left = 3/2
We can change to 3/2 to a mixed number to give us 1
Therefore Erwin have 1 gallons of lemonade left