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Alona [7]
3 years ago
13

5/x=x+2/3 . Multiply each side by the common denominator to find the quadratic equation equivalent to this equation.​

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
8 0

Answer:

C. x^2+2x-15=0

Step-by-step explanation:

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What are the coordinates of point F
densk [106]

Answer:

(4,-2.5)

Step-by-step explanation:

first one is x cordination...it is under the 4

second one is Y cordination..its between -2 and -3

If you understand my answer.mark me as Brainliest...If not...Mark me as BrAiNlEss...☺️

3 0
3 years ago
THE FUNCTION ARCSINE CAN ALSO BE DEFINED AS?
vodomira [7]
The arcsine, \sin^{-1}, is the inverse of the \sin function. This means that it takes as <em>inputs </em>what would usually be <em>outputs </em>for the \sin function and produces as <em>outputs </em>what would usually be <em>inputs </em>for the \sin function.

This can be particularly useful when you're trying to find an angle on a right triangle, but you've only been given the lengths of the sides. To find any angle \theta in a right triangle, just take \sin^{-1} \frac{o}{h}, where o is the side opposite \theta and h is the hypotenuse of the right triangle.

3 0
3 years ago
Determine the equation of a line that passrs through the point (4,-1) and also parallel to y=3x+4
nexus9112 [7]
First, plug in the given point into y=mx +b to find b (the y-intercept of the line). Use the same slope (m) in the equation since parallel lines have the same slope (3 in this case).

-1 = 3(4) +b
-1 = 12 + b Subtract 12 to both sides.
-13 = b

Now, put your m and b into y=mx+b.

The final answer/equation of your line is:

y=3x -13
5 0
3 years ago
What term describes a pair of vertical angles that are also supplementary: acute obtuse right straight?
IgorC [24]
Your answer would be straight!!
7 0
4 years ago
Read 2 more answers
What is the distance from the point (a, −b, −4) to the origin?
laiz [17]

Answer:

  \sqrt{a^2+b^2+16}

Step-by-step explanation:

The distance (d) between two points in 3 dimensions is ...

  d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

Then the distance between (a, -b, -4) and (0, 0, 0) is ...

  d = √((a -0)² +(-b -0)² +(-4 -0)²)

  = √(a² +b² +16)

6 0
3 years ago
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