Question

PLEASE HELP ME GUYS!!! I need immediate help on the 2 above

Answer 1

Answer:

The first answer is d and second answer is a

Step-by-step explanation:

     $\sum_{i=1}^{11}{(3i^2-8)}$

     $\sum_{i=1}^{11}{(3i^2)}-\sum_{i=1}^{11}8$

    $3\sum_{i=1}^{11}{(i^2)}-\sum_{i=1}^{11}8$

    3×n×(n+1)×(2n+1)/6 - 8×n

    Putting n = 11

    3×11×22×23/6 - 8×11

    1430

     The answer is 1430 option d

     We have to find an expression for 10 terms of the series  3/4 + 9/8 +    

     3/2...................................................

    $\sum_{i=1}^{10}(3n/8+3/8)$

     Evaluating the the expansion we get the first option as answer by

     substituting the values of i's

     The answer is option a $\sum_{i=1}^{10}(3n/8+3/8)$