Answer:
see explanation
Step-by-step explanation:
Given the 3 equations
3x + 5y + 5z = 1 → (1)
x - 2y = 5 → (2)
2x + 4y = 11 → (3)
Use (2) and (3) to solve for x and y
Multiply (2) by 2
2x - 4y = 10 → (4)
Add (3) and (4) term by term
4x = 21 ( divide both sides by 4 )
x = ![\frac{21}{4\\}](https://tex.z-dn.net/?f=%5Cfrac%7B21%7D%7B4%5C%5C%7D)
Substitute this value of x into (3)
2 ×
+ 4y = 11
+ 4y = 11 ( subtract
from both sides )
4y =
( divide both sides by 4 )
y = ![\frac{1}{8\\}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B8%5C%5C%7D)
Substitute the values of x and y into (1) and solve for z
3 ×
+ 5 ×
+ 5z = 1
+
+ 5z = 1
+ 5z = 1 ( subtract
from both sides )
5z = -
( divide both sides by 5 )
z = - ![\frac{123}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B123%7D%7B40%7D)
Solution is
x =
, y =
, z = - ![\frac{123}{40}](https://tex.z-dn.net/?f=%5Cfrac%7B123%7D%7B40%7D)
2x^2=4x
I'm pretty sure this is it because there are only 2 like terms so you can't combine anything with 4x.
The image of the arrow is missing, so i have attached it.
Answer:
A_t = 69.5 cm²
Step-by-step explanation:
In a second image attached, I have divided the arrow into triangle and rectangle.
From the second image,
A1 is area of triangle while A2 is area of rectangle
Area of triangle is; A1 = ½bh
Our triangle base is given as 9 cm.
To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.
Thus; height of triangle; h = 11 - 8 = 3cm
Thus;
A1 = ½ × 9 × 3
A1 = 13.5 cm²
Formula for area of rectangle is;
A2 = length × breadth
A2 = 8 × 7
A2 = 56 cm²
Thus, total area of arrow is;
A_t = A1 + A2 = 13.5 + 56
A_t = 69.5 cm²
Answer:
2n+22
Step-by-step explanation:
(n+11)2=
2n+22
Answer:
5x-7+8=-27
Step-by-step explanation:
5x-7+8=-27