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slava [35]
3 years ago
9

A rectangular room is 3 meters longer than it is wide, and its perimeter is 18 meters. Find the dimension of the room.

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0

Answer: the length is 6 meters and with is 3 meters.

Step-by-step explanation:

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Please help with hair question- it’s in the photo
Levart [38]
Salutations!

Growth meters per second = 4.8 × 10^{-9}

First, you need to convert standard form into a normal number.

4.8 × 10^{-9} = 4.800000000

a) In one day there are 24 hours, therefore you will multiplying 4.800000000 and 24

4.800000000 × 24 = 115.2  = 115.2 × 10^{-9} (standard form)

b) 365 days in a year, so multiply 4.800000000 and 365

4.800000000 × 365 = 1752 = 1.7 × 10^{3} (standard form)

Hope I helped (:

have a great day!
3 0
3 years ago
Which statements about the relationship between the two angles below are true? Check all that apply ZC=LT
Ne4ueva [31]

Answer:

The last one, angle D equals to angle T

Step-by-step explanation:

Using the theorem of the triangle we know that the total number measure of the angles is 180 degrees. Therefore, solving the second triangle will give us that the angle T is equal to 60.

This is equal to angle D.

Hope this helps.

6 0
3 years ago
Compare |5| and |-15| using <,> or =
natka813 [3]
The answer is < because |-15| is farther from zero
5 0
4 years ago
You watched a movie that lasted 2 2 /3 hours and then went out to eat for 2 3 /4 hours. How many hours in all did the movie and
Alexeev081 [22]

Answer:

Step-by-step explanation:

Add together:  2 2/3 hrs and 2 3/4 hrs:

First determine the LCD of these two fractions.  The LCD here is 3*4 = 12.

Rewrite the given times using this LCD:

2 8/12 + 2 9/12

Adding 2 and 2 results in 4; adding 8/12 and 9/12 results in 17/12, or 1 5/12.

The final result is 4 + 1 5/12, or 5 5/12.

The movie and dinner together lasted 5 5/12 hrs.

If movie and dinner started at 3:00, dinner would have finished at

3:00 + 5:5/12, or

8:25 p.m. (since 5:5/12 is the same as 5:25).

Finished eating at 8:25 p.m.

4 0
3 years ago
Read 2 more answers
Given the following triangle side lengths, identify the triangle as acute, right or obtuse. Show your work. a. 5 in, 6 in, 7 in
Ede4ka [16]
These are the formulas that will help you determine which type of triangle they are:

a^2+b^2 < c^2      ----> Obtuse Triangle

a^2+b^2 > c^2      ----> Actue Triangle

a^2+b^2 = c^2      ----> Right Triangle

Okay so now that you know that information, lets get into it :)

a. 5 in, 6 in, 7 in

You're going to take the smallest numbers, 5 and 6, and add them, if it equals a larger number than 7 then its a triangle and you have to determine if its an obtuse, right or acute triangle. In this case it is a triangle because 5 + 6 = 11 aka larger than 7.

The way you'll set this up is:

5^2 + 6^2 = 7^2

solve
25+36=49      ----->     25+36=61

61 > 49 or a^2 + b^2 > c^2

61 > is greater than 49

If you look ate the formulas that are above, this is an acute triangle.

b. 18 in, 9 in, 12 in

In this question, 9 and 12 are the smallest numbers that equal 21 and 21 is larger than 18 so, this is a triangle.

9^2 + 12^2 = 18^2

Solve
81 + 144 = 324      ---->      81 + 144 = 225

225 < 324 or a^2+b^2 < c^2

225 < is less than 324

If you look ate the formulas that are above, this is an obtuse triangle.

Something to just remember:

Sometimes you'll get a question which is like,
4 in, 5 in, 10 in
In this situation, if you add the smallest numbers which are, 4 and 5, you get 9, which is less than the larger number you have, 10. That means it is not a triangle. Just something to be aware about :)

I hope this helped you!






4 0
4 years ago
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