Answer: y=5x+7
Step-by-step explanation:
If you draw a graph or use a graphing calculator the points and then connect them you will see that the y-intercept is 7 and the slope is 5/1. Slope intercpt form is y=mx+b. So the equation is y=5x+7.
Find the line that is normal to the parabola at the given point
remember that normal means perpendicular
perpendicular lines have slopes that multiply to -1
we can use point slope form to write the equation of the line since we are given the point (1,0)
we just need the slope
take derivitive
y'=1-2x
at x=1
y'=1-2(1)
y'=1-2
y'=-1
the slope is -1
the perpendicular of that slope is what number we can multiply to get -1
-1 times what=-1?
what=1
duh
so
point (1,0) and slope 1
y-0=1(x-1)
y=x-1 is da equation
solve for where y=x-1 and y=x-x² intersect
set equatl to each other since equal y
x-1=x-x²
x²-1=0
factor difference of 2 perfect squares
(x-1)(x+1)=0
set to zero
x-1=0
x=1
we got this point already
x+1=0
x=-1
sub back
y=-1-(-1)²
y=-1-(1)
y=-1-1
y=-2
it intersects at (-1,-2)
The probability that the marble taken out is yellow is 1/4
Step-by-step explanation:
Total marbles = 12
Yellow marbles = 3
Probability that the marble taken out is yellow= No of yellow marbles/total marbles.
Probability that the marble taken out is yellow= 3/12
Probability that the marble taken out is yellow= 1/4
So, the Probability that the marble taken out is yellow is 1/4
Keywords: Probability
Learn more about Probability at:
#learnwithBrainly
Answer: C. (-4, -2)
<u>Step-by-step explanation:</u>
First, eliminate one of the variables and solve for the remaining variable:
2x - 5y = 2 → 3(2x - 5y = 2) → 6x - 15y = 6
3x + 2y = -16 → -2(3x + 2y = -16) → <u> -6x - 4y = 32</u>
-19y = 38
y = -2
Next, replace "y" with -2 into either of the original equations to solve for x:
2x - 5y = 2
2x - 5(-2) = 2
2x + 10 = 2
2x = -8
x = -4
x = -4, y = -2
<u>Check:</u>
Plug in the x- and y-values into the other original equation:
3x + 2y = -16
3(-4) + 2(-2) = -16
-12 + -4 = -16
-16 = -16 