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Alexandra [31]
3 years ago
14

____________is the practice of putting students into specific curriculum groups based on their test scores and other factors.

Mathematics
1 answer:
Tresset [83]3 years ago
3 0

Answer: Tracking is the practice of putting students into specific curriculum groups based on their test scores and other factors.

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3. MGSE9-12.N.RN.3 Which statement is true about the value of 5(6 + √9)?
Katarina [22]

Answer:

A

Step-by-step explanation:

6 and the square root of 9 are both rational numbers and they are being multiplied by 5 which is also rational.

3 0
2 years ago
A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions
faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that  

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=length \times width

Area of rectangular parking lot = length of rectangular parking plot \times width of the rectangular parking

\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}

But it is given that Area of rectangular parking lot = 15000 square feet

\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is  </u></em>

{ax^{2}+\mathrm{b} x+\mathrm{c}=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}

\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet  

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0
2 years ago
Measure the width of the paper clip to the nearest millimeter
Elenna [48]

Answer: 4/10

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Circle X is shown in the diagram.
GaryK [48]

Answer:

m<1 = 1/2(a+b)

Step-by-step explanation:

First, you have to add the two different side angles and then divide by two. I just took my quiz and got this.

7 0
3 years ago
The circumstance of a circle is 9pie cm. What is the diameter?
8090 [49]
The diameter is 9.
Circumference=pi*diameter
9 pi/pi=9

Hope this helped☺☺
6 0
2 years ago
Read 2 more answers
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