Let V, be the rate in still water and let C = rate river current
If the boat is going :
upstream, its rate is V-C and if going
downstream, its rate is V+C,
But V = 5C, then
Upstream Rate: 5C - C = 4 C
Downstream rate: 5C+C = 6C
Time = distance/Rate, (or time = distance/speed) , then:
Upstream time 12/4C and
Downstream time: 12/.6C
Upstream time +downstream time:= 2h30 ' then:
12/4C + 12/.6C = 2.5 hours
3/C + 2/C = 5/2 (2.5 h = 5/2)
Reduce to same denominator :
5C = 10 and Rate of the current = 2 mi/h
I hope you will like my answer
You would do 29.85 ÷ 3 which equals 9.95. You would do the in verse operation. Hope I helped you.
Answer:
°
Step-by-step explanation:
Because the diagonal lines are marked with arrows, we know that they are parallel. The two angles that are marked with measures are same-side interior angles. Same-side interior angles of parallel lines are supplementary, meaning that the sum of their measures is 
°.
Now, with all of this information, we can set up the following equation and solve for 
:
(Simplify LHS by combining like terms)
(Subtract 
from both sides of the equation to isolate )
(Simplify)
(Divide both sides of the equation by 
to get rid of 's coefficient)
° (Simplify)
Hope this helps!
