Answer:
1. At Kohls Mrs. House would pay $45.00 because %25 = $15 so I just subtracted %.60.00-$15.00.
2.((Number × Percent/100)) + Number
((38 × 15/100)) + 38
5.7 + 38
= 43.7
3. I say that Mrs. House should go-to target. And just by $1.30.
At Kohls, the speaker would be at $45.00.
At target, the speaker would be at $43.70.
$45.00 - $43.70 = $1.30
Step-by-step explanation:
Answer:
15 is the middle number
Step-by-step explanation:
BECAUSE IF YOU COUNT FROM THE LEFT AND RIGHT AND WHICH NUMBER APPEARS IN THE MIDDLE IS YOUR MEDIAN
Answer:
How long did Yumi spend picking up litter?
6 HOURS!!!!
Step-by-step explanation:
just took it on ed:)
Answer:
B = 1.875
Step-by-step explanation:
given that A varies directly as B and inversely as C then the equation relating them is
A = 
← k is the constant of variation
to find k use the condition A = 12 when B = 3 and C = 2 , then
12 = 
( multiply both sides by 2 to clear the fraction )
24 = 3k ( divide both sides by 3 )
8 = k
A = 
← equation of variation
when A = 10 and C = 1.5 , then
10 = 
( multiply both sides by 1.5 )
15 = 8B ( divide both sides by 8 )
1.875 = B
Answer:
11 people will get both the prizes.
Step-by-step explanation:
In this question we need to find common integral multiples of 5 and 7 under 400. As you can see in the figure 35th person is the first one to get both ipod and psp. The LCM (least common multiple) of 5 and 7 which is 35 (!!! <em>I hope you know how to LCM of two integers </em>).
Therefore the integral multiples of 35 will be same as the common multiples of 5 and 7. So, figuring out the number of integral multiples of 35 under 400 will give the answer.
To do that divide the number 400 with 35. On performing the division the quotient will be 11 and the remainder will be 15.
Therefore 11 persons out of 400 will get both the prizes.
Similarly if you want to find the number of person getting ipod then divide 400 with 5. The quotient will be 80. ∴ 80 people will get ipod.
And for psp, divide 400 with 7. The quotient will be 57. ∴ 57 people will get psp.
In these divisions, consider just the quotient, here remainder is of no use.
