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11111nata11111 [884]
4 years ago
14

How may bit strings are there of length 8

Computers and Technology
2 answers:
sleet_krkn [62]4 years ago
7 0

Answer:

2^8=256 different strings

Explanation:

A <em>bit</em> can either store a 1 or a 0, this gives you 2 different 1-bit strings (0, 1), 4 different 2-bit strings (00, 01, 10, 11), and in general, 2^n strings for an n-bit string. Why 2^n? Well, for every bit, we have 2 choices, either a 0 or a 1, which means we double the number of possible strings with every additional bit. So, in a string with a length of 8 bits, we'll have 2^8=256 possible choices for strings.

deff fn [24]4 years ago
5 0

Answer:

there are 256 bits. there 256 values u can store in a byte

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Answer:

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Explanation:

#include<iostream.h>

#include < conio.h>

bool isVowel(char b)

{

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For swaoing the vowels

string reverseVowel ( String str)

{

int j = 0;

string v ;

for ( int i= 0 ; str [i]]!='0'; i++)

if( isv(str[i]))

v[j++] = str[i[;

for ( int i = 0; str[i]! = '0' ; i++

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}

int main ()

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7 0
3 years ago
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Answer:

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<em />

Explanation:

To answer this question, I'll make use of the following attachment

<em>Where</em>

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<em />

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4 years ago
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