Question

How may bit strings are there of length 8

Answer 1

Answer:

$2^8=256$ different strings

Explanation:

A bit can either store a 1 or a 0, this gives you 2 different 1-bit strings (0, 1), 4 different 2-bit strings (00, 01, 10, 11), and in general, $2^n$ strings for an n-bit string. Why $2^n$? Well, for every bit, we have 2 choices, either a 0 or a 1, which means we double the number of possible strings with every additional bit. So, in a string with a length of 8 bits, we'll have $2^8=256$ possible choices for strings.

Answer 2

Answer:

there are 256 bits. there 256 values u can store in a byte