All categories

3 years ago

The conversion of decimal 0.0625 into its binary equivalent. Explain.

Computers and Technology

1 answer:

Rashid [163]3 years ago

4 0

D. 0.0001.......first the zero before the decimal point is devided by 2....so it gives out 0 as a reminder so u right 0. at first then to do the part after decimal...first multiply 0.625 by 2 which gives out 0.125 as a fractional number so 0 would be the number after "0." ...and again the answer 0.125 is multiplied by 2 which gives out 0.25....so again we get a zero as an integer so now it would be "0.00..." ....again multiply 0.25 by 2 which gives out 0.5....again the integer is 0....so we add another 0 after 0.00....which would then become 0.000.....after that again multiply 0.5 by 2 which would give 1 as a result....as the fractional part is over, u need to stop here....so add that 1 after the 0.000 which gives 0.0001 as a final result.

You might be interested in

Consider the following import statement in Python, where statsmodels module is called in order to use the proportions_ztest meth

den301095 [7]

Answer:

a. count of observations that meet a condition (counts), total number of observations (nobs), Hypothesized value of population proportion (value).

Explanation:

In other to use the proportion_ztest method, the need to make import from the statsmodel module ; statsmodels.stats.proportion.proportions_ztest ; this will allow use use the Z test for proportion and once this method is called it will require the following arguments (count, nobs, value=None, alternative='two-sided', prop_var=False)

Where;

nobs = number of observations

count = number of successes in the nobs trial or the number of successes for each independent sample.

Value = hypothesized value of the population proportion.

7 0

3 years ago

Variables make it easier to do what?

defon

D. Make changes to your code
Variables allow the ability to easily substitute numbers for other numbers.

8 0

3 years ago

study the picture of the simulation and the graph above. based on the information obtained from your study of the simulation and

andreyandreev [35.5K]

This is how you know i’m def gonna fail my university class this year :/

6 0

2 years ago

A switch that is configured to use the Spanning Tree Protocol will place a port in ____________ mode if sending traffic to it ma

Rashid [163]

Answer:

Blocking Mode

Explanation:

Spanning Tree Protocol is used to allow path redundancy in the network without creating cycles/circles also called loops.

When two parts of the switched network are connected via two or more Layer 2 switches this result in a loop.

This affects the performance of the network as the result of broadcast packets flooding.

STP puts one port of the switch to forwarding mode and the rest of the ports within the same part of the network to the blocking mode to avoid broadcast packet flooding. STP puts all the ports that are allowing redundant paths to blocking mode and the one port that is left after this is placed in forward mode.

Spanning Tree Algorithm is used by STP to determine the optimal path of switch to the network.

Bridge Protocol Data Units are used to share the information about the optimal path determined by the spanning tree algorithm with other switches.

This information helps STP to eliminate the redundant paths.

So this is how STP allows only one active path to the destination while blocking all other paths to avoid switching loop.

6 0

3 years ago

The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices

erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;

import java.util.Arrays;

public class Main {

public static void main(String args[]) {

Scanner input = new Scanner(System.in);

int row, col;

System.out.print("Rows: "); row = input.nextInt();

System.out.print("Cols: "); col = input.nextInt();

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}

public static int[] findmax(int[][] Array2D,int row, int col) {

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i;

maxitem[1] = j; } } }

return maxitem;

}

Explanation:

The next two lines import the scanner and array libraries

import java.util.Scanner;

import java.util.Arrays;

The class of the program

public class Main {

The main method begins here

public static void main(String args[]) {

The scanner function is called in the program

Scanner input = new Scanner(System.in);

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input

System.out.print("Rows: "); row = input.nextInt();

This next instructions prompt the user for columns and get the column input

System.out.print("Cols: "); col = input.nextInt();

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

This calls the findmax function. The returned array of the function is saved in maxarray

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col) {

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i; -- The row position is saved in index 0

maxitem[1] = j; -- The column position is saved in index 1} } }

This returns the 1 d array

return maxitem;

}

7 0

3 years ago