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3 years ago

14

At 3pm, the outside temperature was 4.f. The temperature then fell steadily by 2.fevery hour for the next four hours. What was t

he temperture at 7pm.

1 answer:

Stels [109]3 years ago

8 0

4 - 2 - 2 - 2 - 2 = -4°F
It falls by 2 every hour. So starting with 4, you minus 2 for every hour that passes until you reach 7pm.
OR
4 - (2 x 4)
Start with 4, minus 2 four times (since it takes 4 hours to reach 7pm from 3pm)

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CONSTRUCT ARGUMENTS Consider three points, (3, 7), (−6, 1), and (9, p) on the same line. Find the value of p. Justify your argum

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Answer:

p=11

Step-by-step explanation:

let A(3,7),B(-6,1),C(9,p) be the points.

or

B(-6,1),A(3,7),C(9,p) are the points in the same line.

let A divides BCin the ratio k:1

$3=\frac{9k+1(-6)}{k+1} \\3k+3=9k-6\\3k-9k=-6-3\\-6k=-9\\k=\frac{-9}{-6} =\frac{3}{2} \\so~ratio~is~\frac{3}{2} :1\\or\\3:2\\again\\7=\frac{3p+2(1)}{3+2} \\5*7=3p+2\\3p=35-2=33\\p=\frac{33}{3} =11$

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La respuesta es 0.05 :)

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3 years ago

What two numbers multiply to -126 and add up to -65

Airida [17]

Xy = -126
x + y = -65

$xy = -126$
$\frac{xy}{x} = \frac{-126}{x}$
$y = \frac{-126}{x}$

$x + y = -65$
$x + \frac{-126}{x} = -65$
$\frac{x^{2}}{x} + \frac{-126}{x} = -65$
$\frac{x^{2} - 126}{x} = -65$
$-65x = x^{2} - 126$
$0 = x^{2} + 65x - 126$
$x = \frac{-(65) \+ \sqrt{(65)^{2} - 4(1)(-126)}}{2(1)}$
$x = \frac{-65 \± \sqrt{4225 + 504}}{2}$
$x = \frac{-65 \± \sqrt{4729}}{2}$
$x = \frac{-65 \± 68.8}{2}$
$x = \frac{-65 + 68.8}{2}$ $or$ $x = \frac{-65 - 68.8}{2}$
$x = \frac{3.8}{2}$ $or$ $x = \frac{-133.8}{2}$
$x = 1.9$ $or$ $x = -66.9$

x + y = -65
  1.9 + y = -65
- 1.9   - 1.9
y = -66.9
  (x, y) = (1.9, -66.9)

or

  x + y = -65
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+ 66.9 + 66.9
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The two numbers that add up to -65 and can multiply to -126 are the numbers -66.9 and 1.9.

3 0

4 years ago

Given parallelogram MNOP, MA = x + 5, AO = y + 2, PA = 3x and AN = 2y

erma4kov [3.2K]

Answer:

The values of x and y are x = 6 and y = 9

Step-by-step explanation:

MNOP is a parallelogram its diagonal MO and PN intersected at point A

In any parallelogram diagonals:

Bisect each other
Meet each other at their mid-point

In parallelogram MNOP

∵ MO and NP are its diagonal

∵ MO intersect NP at point A

- Point A is the mid-point pf them

∴ MO and NP bisect each other

∴ MA = AO

∴ PA = AN

∵ MA = x + 5

∵ AO = y + 2

- Equate them

∴ x + 5 = y + 2 ⇒ (1)

∵ PA = 3x

∵ AN = 2y

- Equate them

∴ 2y = 3x

- Divide both sides by 2

∴ y = 1.5x ⇒ (2)

Now we have a system of equations to solve it

Substitute y in equation (1) by equation (2)

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∴ - 0.5x + 5 = 2

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∴ - 0.5x = -3

- Divide both sides by - 0.5

∴ x = 6

- Substitute the value of x in equation (2) to find y

∵ y = 1.5(6)

∴ y = 9

The values of x and y are x = 6 and y = 9

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3 years ago