Answer:
I think it's
B)2
<em>I</em><em> </em><em>hope</em><em> </em><em>that</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em> </em><em /><em />
Answer:
5 7/24
Step-by-step explanation:
First, you need to make the denominators the same. When you multiply 6 with 4 you get 24, and if you multiply 8 with 3 you get 24. Then you have to multiply the numbers you multiplied with the denominators with the numerator. So, 5 x 4 is 20 and 3 x 1 is 3. Once you put all the numbers together it should look like this: 3 20/24 and 9 3/24. In order to find the answer, you have to subtract the numbers from each other. Which would look like this: 9 3/24 - 3 20/24. But as you can see you can't subtract 3 from 20. So you have to carry the 9. This means you have to subtract 9 from 1, and then you have 27 for the numerator, this then makes it possible to subtract from 20. So then the fractions subtracted from each other is 7 and the whole numbers subtracted from each other is 5 (because the 9 is now 8 since we subtracted one from it). Whole numbers subtracted from each other: 5. Fractions subtracted from each other: 7/24. Add it together you get 5 7/24.
Numerator - the number above the fraction, ex 3 in 3/4
Denominator - the number below the fraction, ex 4 in 3/4
This is an equation of exponential decay
y(t) = a b^ t where a is the initial amount
b is the decay factor
t is the time in years
b is found by taking 1 and subtracting the percent it decreases in decimal form
Letting t =4
y(t) = 260 million * ( 1- .011) ^ 4
=248.7473796 million
=24874737.96
Rounding to a whole number
= 24874738
9514 1404 393
Answer:
Step-by-step explanation:
There are <em>an infinite number of possibilities</em>. Any vector whose dot-product with p is zero will be perpendicular to p.
Let m = 0i +1j +ak. Then we require ...
m·p = 0 = 0×1 +1×2 +a(-2) ⇒ 0 = 2 -2a ⇒ a = 1
m = 0i +1j +1k
__
Let n = 2i +0j +bk
n·p = 0 = 2×1 +0×2 +b(-2) ⇒ 2 -2b = 0 ⇒ b = 1
n = 2i +0j +1k
Answer:
Step-by-step explanation:
When you add, multiply or subtract polynomials, the operation results in another polynomial.
When dividing polynomials, the operation may not result in another polynomial. In this case you normally end up with rational expression in the fraction form.
This operation is said not closed.
In our case this is option D.
