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Mazyrski [523]
3 years ago
7

A rock is thrown up from the ground at a velocity of 84 feet per second. The formula h = -16t2 + 84t gives the rock's height in

feet after t second. What is the maximum height of the rock?
Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

h = 110.24 m

Step-by-step explanation:

It is given that,

A rock is thrown up from the ground at a velocity of 84 feet per second. The formula h = -16t^2 + 84t gives the rock's height in feet after t second.

We need to find the maximum height of the rock. For maximum height put \dfrac{dh}{dt}=0

So,

\dfrac{d( -16t^2 + 84t)}{dt}=0\\\\-32t+84=0\\\\t=\dfrac{84}{32}\\\\t=2.62\ s

Put t = 2.62 s in the equation of height. So,

h = -16(2.62)^2 + 84(2.62)\\\\h=110.24\ m

So, the maximum height of the rock is 110.24 m.

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