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Alenkinab [10]
2 years ago
14

How are luminosity and magnitude related?(In your own words) ​

Biology
1 answer:
statuscvo [17]2 years ago
8 0

Answer:

Luminosity is an intrinsic(natural) measurable property of a star independent of distance. The concept of magnitude, on the other hand, incorporates distance. The apparent magnitude is a measure of the diminishing(decrease) flux of light as a result of distance according to the inverse-square law.

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What are some ways that living things can be classified? What characteristics should we look at when putting living things into
ANTONII [103]

The classification of living things includes 7 levels: kingdom, phylum, classes, order, families, genus, and species. Characteristics such as appearance, reproduction, mobility, and functionality are just a few ways in which living organisms are grouped together. These specialized groups are collectively called the classification of living things.

Hope this helps :)

7 0
2 years ago
The____
natka813 [3]

b. Cerebrum

and is responsible for the integration of sensory and neural functions.

5 0
2 years ago
Bacteria are able to reproduce very quickly through a process known as binary fission. Binary fission requires only one parent.
kkurt [141]

Answer:

this is called asexual reproduction

Explanation:

it is where one parent makes a clone of themselves through budding.

7 0
2 years ago
How would the DNA in an eye cell and a heart cell compare?
ankoles [38]

Answer:

Almost all of the cells in your body share the same DNA as was found in that first cell. Eyes and heart are so different because different set of problems are made in the various eyes and heart cell

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a

4 0
3 years ago
1. What is the total magnification of an object if the ocular lens magnification is 20x and the objective lens magnification is
V125BC [204]

1. Answer: 900x

A typical microscope has two lens: ocular lens which located near the eye, and objective lens which located near the object. The image will undergo magnification of both lens. The total magnification of the object would be the product of both lens multiplication, not the sum. The multiplication will be: 20x * 45x= 900x

total mag= ocular * object

total mag= 20x * 45x

total mag= 900x


2.  Answer: 100x

The total magnification of the object would be the product of both lens multiplication. If the total magnification 1000x, that mean it was the product of ocular lens and objective lens. If ocular lens magnification is 10x, objective lens magnification would be:

total mag= ocular * object

1000x= 10x*object

object=1000x/ 10x=

object=100x

3. Answer: 0.2 mm

The area of the microscope that can be viewed by the eye should be the same. But since the magnification is different, the actual area that it represent will be different. Microscope with bigger magnification will have smaller diameter of the field of view(DFV).  Remember that micrometer(μm) is 1/1000 of millimeter(mm). The DFV would be:500 μm/ ( 1000x/400x)= 200μm= 0.2 mm


4. Answer: 750μm

This question is similar to number 3 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm) .

The DFV of a 10x objective lens is 3 mm. Then the DFV of 40x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 3mm/ ( 40x/10x)= 0.75 mm= 750μm

5. Answer: 125μm x 37.5μm

The lens DFV of microscope from question 4 is 750μm, so the width and length of the area would be 750μm.

If 6 organisms could fit across the DFV if they were laid end-to-end, the length would be: 750μm/ 6 organism= 125μm

If 20 organism could fit is stacked side by-side, then the width would be: 750μm/ 20 organism= 37.5μm

6. Answer: 6mm

This question is similar to number 3 and number 4 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm).

The DFV of a 100x objective lens is 1.5 mm. Then the DFV of 25x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 1.5mm/ (100x/25x)= 6 mm


7.Using the 100x objective lens from question 6, you estimate 12 organisms could fit across the DFV if they were laid end-to-end and 30 could fit is stacked side-by-side. What is the length and width of this organism (in microns)?  

Answer: 0.5mm x 0.2mm or 500μm x 200μm

The lens DFV of microscope from question 6 is 6 mm, so the width and length of the area would be 6 mm.

If 12 organisms could fit across the DFV if they were laid end-to-end, the length would be: 6mm/ 12 organism=0.5mm

If 30 organism could fit is stacked side by-side, then the width would be: 6mm/ 30 organism= 0.2mm

6 0
3 years ago
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