Question

Calculate the slip of the line that contains the points (2,-3) and (6,-3

Answer 1

Hello!

Step-by-step explanation:

Slope: $\frac{Y^2-Y^1}{X^2-X^1}=\frac{rise}{run}$

$\frac{(-3)-(-3)=-3+3=0}{6-2=4}=\frac{0}{-4}=0$

Therefore, the slope is 0.

I think the answer is 0.

Have a nice day! :)

Have a great day!

-Charlie

:)

:D

Answer 2

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{-3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-(-3)}{6-2}\implies \cfrac{-3+3}{4}\implies \cfrac{0}{4}\implies 0$