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rodikova [14]
4 years ago
13

F(x)=6x^3 - 3x^2 4x- 15 for x = -3.5

Mathematics
1 answer:
Airida [17]4 years ago
8 0

Answer:

Factor by grouping. (3r + 5)(r-3)

Step-by-step explanation:

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Please write an addition statement that is equivalent to 49 ÷ -7
Zanzabum

Answer:

84 ÷ -12 = -7

21 ÷ -3 = -7

Step-by-step explanation:

49 ÷ -7 = -7

Means that __ ÷ __ must equal -7

There are many options, here are a few:

84 ÷ -12 = -7

or -84 ÷ 12 = -7

21 ÷ -3 = -7 etc

5 0
3 years ago
How tall would I  be if i were 54 inches   How tall would I be if i were 58 inches?   How tall would i be if Iwere 59 inches?
baherus [9]
<span>So the question is how tall would a person be in three cases, 54 inches, 58 inches and 59 inches. Since the height measure are feet and inches and one feet has 12 inches, this is the first case: 54 inches = 4*12 inches + 6 inches = 4 feet and 6 inches = 4'6''. Second case: 58 inches= 4*12 + 10 inches= 4 feet and 10 inches = 4'10'' and third case: 59 inches= 4*12 inches + 11 inches= 4 feet and 11 inches = 4'11''. </span>
6 0
3 years ago
Use the formula r = (F/P)^1/n - 1 to find the annual inflation rate to the nearest tenth of a percent. A rare coin increases in
Dmitriy789 [7]
Go ask your professor for advice it is much better for any normal person
7 0
4 years ago
On the first season of "The Biggest Loser",
amid [387]

Answer:

33%

Step-by-step explanation:

311-208=103 ponds lost

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4 0
3 years ago
NEED ANSWER ASAP- MARK AS BRANLIEST
azamat

Answer:

  x = 1 +√5

Step-by-step explanation:

There are different formulas for the area of a triangle available, depending on the given information.

<h3>Formulas</h3>

When two sides and the angle between them are given, the relevant area formula is ...

  Area = 1/2(ab)sin(C)

When the base and height of a triangle are given, the relevant area formula is ...

  Area = 1/2bh

<h3>Equal Areas</h3>

The problem statement tells us the two triangles shown have equal areas. That means the two formulas will give the same result.

  Area from angle = Area from base/height

  1/2(x·x)sin(30°) = 1/2(x-2)(x+1)

  x² = 2(x² -x -2) . . . . . . . . . . . use sin(30°) = 1/2, multiply by 4

  x² -2x -4 = 0 . . . . . . . . subtract x², eliminate parentheses

  (x -1)² = 5 . . . . . . . . . add 4+1 to complete the square

<h3>Value of x</h3>

  x = 1 ± √5 . . . . . . take the square root, add 1

The value of x must be greater than 2 in order for the triangle side lengths to be positive. (x-2 > 0) This means x = 1-√5 is an extraneous solution.

The value of x is 1 +√5.

5 0
3 years ago
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