(-2.-1). You can just plug in the numbers. -1=-6+5 is -1=-1. -1-2(-2)=3 is -1--4=3 is 3=3.
Answer:
First equation x=2, Y=9, Second Eq, x=2, y=1
Step-by-step explanation:
X+Y=11
2X-Y=-5 by substitution Y=11-X
So, 2x-(11-x)=-5, 2x-11+x=-5, 3x=6, x=2. Thus, Y=11-2=9
2x+y=5
3x-2y=4
so, y=5-2x
Thus, 3x-2(5-2x)=4
3x-10+4x=4, 7x=14, x=2, Thus, Y=5-2(2)= 1
Answer:
Step-by-step explanation:
The square root property requires a quantity squared by itself on one side of the equation. The only quantity squared is x, so divide both sides by 2 before applying the square root property.
The x variable should be isolated on one side of the equation. The x variable is squared so before performing the square root property where we take the square root of both sides, we divide both sides by 2, then take the square root of both sides.
Dividing both sides by 2.
Taking the square root of both sides.
Use the identity
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x = 1 + tan^2x - 2 tan x
0 = -2 tanx
tan x = 0
x = 0, π
π is an extraneous root because sec 180 = -1
So the answer is 0 degrees
First: The student rotated the figure 90° clockwise.
Second: The student reflected across the x-axis.
Answer: Option C. <span>The student rotated the figure 90° clockwise rather than 90° counterclockwise.</span>
